Answer:

Explanation:
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In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

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Answer:
31.36 KJ/mol
Explanation:
mass of the liquid = 74.0 g
heat of vaporization = 21.40 kJ/mol
constant boiling point temperature = 24.09 °C
heat required to vaporize 74.0g = heat of vaporization × mole
mole of Chloromethane = 74.0 g / 50.49 (g/mol) = 1.466 mol
energy required = 1.466 mol × 21.40 KJ/mol = 31.36 KJ/mol