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labwork [276]
3 years ago
9

How many atoms are in FeS₂?

Chemistry
1 answer:
hammer [34]3 years ago
6 0

Surface model,we used a supercell of

16.1106×16.1106×18.0 And a model of a 3 × 3

9 atoms..

<h3><u>if</u><u> this</u><u> answer</u><u> helps</u><u> you</u><u> plz</u><u> mark</u><u> as</u><u> brainlist</u><u>.</u><u>.</u></h3><h2><u>But</u><u>,</u><u> don't</u><u> </u><u>report </u><u>my</u><u> answer</u><u>.</u><u>.</u></h2>

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A gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the con
sladkih [1.3K]

Answer:

\boxed {\boxed {\sf 2. \ 157 \ kPa}}

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using <u>Boyle's Law.</u> This states that the pressure is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

275 \ kPa *20.0 \ L=P_2V_2

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

275 \ kPa *20.0 \ L=P_2* 35.0 \ L

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}

\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2

The units of liters cancel.

\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2

\frac {5500}{35.0} \ kPa= P_2

157.142857 \  kPa=P_2

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

157 \ kPa= P_2

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

8 0
3 years ago
On the periodic table, what is a group? For the main groups, what characteristic
rjkz [21]
<h3>Answer: Mendeleev’s Periodic Table was built by listing the known elements in order of increasing atomic mass and grouping the elements by their properties (such as reactivity and formula of oxides). In one or two cases, he discovered that he had to put a lower atomic mass element after a higher atomic mass element because the table which went strictly by increasing atomic mass produced groups with inconsistent properties. He also left blanks in the table.</h3>

In modern times, we know that the elements in a given group (also known as a family or column) have the same number of valence electrons, with ground state configurations having a consistent pattern, for instance:

F 1s2 2s2 2p5, Cl 1s2 2s2 2p6 3s2 3p5, Br 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5, etc.

Of course, the ground state configurations play a major role in determining how an element reacts and what compounds it forms. Thus, the elements in a given group have similar properties.

The structure of the table also predicts how the properties vary. For instance, atomic radius increases down a group as does metallic character.

<h3>Hope this helps have a awesome day/night✨</h3>

Explanation:

4 0
3 years ago
I have to write chemical formula and the electron-dot for each of the product and also show electric charge if ions are formed
Ilya [14]

bnswer

a. O +O / → O₂

b. K + Cl → KCl

c. C + O → CO

d. H + F → HF

e. I + I → I₂

f. S + O + O → SO₂

g. Na + Na + S → Na₂S

h. Li + Cl → LiCl

i. Ca + Br + Br → CaBr₂

j. N + N → N₂

A

8 0
1 year ago
Determine the spec gravity of 500 mL alcohol if the density is 0.79g/ml
slava [35]

Answer:

S.G = 0.79.

Explanation:

Hello there!

In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:

S.G=\frac{\rho _{alc}}{\rho _w}

Thus, we plug in the densities to obtain:

S.G=\frac{0.79g/mL}{1g/mL}\\\\S.G=0.79

Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.

Regards!

8 0
3 years ago
What distinguishes effusion from diffision? How are these processes similar?
zvonat [6]

Answer:

In effusion, a substance escapes through a tiny pinhole, or other hole whereas diffusion is the spreading out of a substance within a dispersing medium.

Effusion and diffusion are similar in terms of rates and speeds.

Explanation:

According to effusion, if there is a small hole in a container, a gas will leak from it. So, in this process a substance escapes through a tiny pinhole, or other hole.

According to diffusion, the two solutions will reach the lowest possible concentration of both, if they are combined and not mixed. So, diffusion is the spreading out of a substance within a dispersing medium.

Effusion and diffusion are similar in terms of rates and speeds.

7 0
4 years ago
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