Answer:
1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies
2) Now let's consider any real number a no matter positive or negative we will have that:
Or in the other case:
So then we can conclude that the expression is a general rule and is true
Step-by-step explanation:
For this case we can verify if the following expression is true or false:
The sum of x and it’s opposite is always zero?
If we want to proof this we need to show that for any number is true.
1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies
2) Now let's consider any real number a no matter positive or negative we will have that:
Or in the other case:
So then we can conclude that the expression is a general rule and is true
I think the answer could possibly be a
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.
Answer:
B I hope this helped!
Step-by-step explanation:
Answer:
The man wins 9 times and looses 11 times in the rock - paper-scissor game.
Step-by-step explanation:
Let us assume that in the game:
Number of times man wins the games = x times
Number of times man loses the games = y times
Total number of attempts = 20
Points after winning = 5
Points after loosing = 2
Now, according to the question:
x + y =20
and 5 x + 2 y = 67
Now, from (1) y = 20-x, put in (2)
5x + 2y = 67 ⇒ 5x + 2(20 -x) = 67
or, 5x -2x = 67 - 40
or, 3x = 27
⇒ x = 27/3 = 9
then y = 20 - x = 20 - 9 = 11
⇒ x = 9 and y = 11 is the solution of the given system.
Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.
