<span>In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The short leg is </span>the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

$
cos(60^o) = \frac{adjacent \ side}{hypotenuse } = \frac{x}{2x} = \frac{1}{2}$

Answer is C. 1:2

7 0

2 years ago

Is -42-10=-52 open, true or false ?

pantera1 [17]

I think the answer is True

8 0

2 years ago

Read 2 more answers

The area of a trapezium is 35cm2.find its altitude if the bases is 6cm and 8cm

r-ruslan [8.4K]

Answer: altitude: 5 cm

Explanation:

$\sf \dfrac{1}{2} ( a + b) h = Area \ of \ trapezium$

[ <u>a and b are bases, h is the altitude</u> ]

Here given:

Area = 35

a = 6

b = 8

h = ?

Solve for altitude:

$\sf \rightarrow \sf \dfrac{1}{2} ( 6 + 8) h = 35 \ \ \ \Rightarrow \ \ \ \dfrac{1}{2} ( 14) h = 35 \ \ \ \ \Rightarrow \ \ \ \ 7 h = 35 \ \ \ \ \Rightarrow \ \ h = \dfrac{35}{7} \ = \ 5$

7 0

1 year ago