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Vesnalui [34]
4 years ago
5

how do I solve how much time does it take for a satellite moving 15000 miles per hour travel to travel once around the earth 249

01 miles ?​
Physics
1 answer:
iogann1982 [59]4 years ago
3 0

Answer:

The time taken by the satellite to orbit earth at its surface, t = 1.66 hr

Explanation:

Given data,

The velocity of the satellite, v = 15000 miles/hr

The distance of travel, d = 24901 miles,

It is equal to the circumference of earth,

So the time taken by the satellite to orbit earth at its surface,

                           v = d/t

                            t = d/v

Substituting the given values in the above equation,

                            t = 24901 / 15000

                              = 1.66 hr

Hence, the time taken by the satellite to orbit earth at its surface, t = 1.66 hr

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To a good approximate, the only external force that does work on a cyclist moving on level ground is the force of air resistance
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Answer:

a. 120 W

b. 28.8 N

Explanation:

To a good approximate, the only external force that does work on a cyclist moving on level ground is the force of air resistance. Suppose a cyclist is traveling at 15 km/h on level ground. Assume he is using 480 W of metabolic power.

a. Estimate the amount of power he uses for forward motion.

b. How much force must he exert to overcome the force of air resistance?

(a) He is 25% efficient, therefore the cyclist will be expending 25% of his power to drive the bicycle forward

Power = efficiency X metabolic power

= 0.25 X 480

= 120 W

(b)

power if force times the velocity

P = Fv

convert  15 km/h to m/s

v = 15 kmph = 4.166 m/s

F = P/v

= 120/4.166

= 28.8 N

definition of terms

power is the rate at which work is done

force is that which changes a body's state of rest or uniform motion in a straight line

velocity is the change in displacement per unit time.

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What would tweezers be used for in a first-aid kit?
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To remove a splinter from the skin.
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Which is the best example of Newton's Second Law of Motion?
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A small ball and a larger ball with greater mass are dropped from a roof. The larger ball strikes the ground with greater force than the smaller ball.
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A 45.0 g hard-boiled egg moves on the end of a spring with force constant 25.0 N/m. Its initial displacement 0.500 m. A damping
leva [86]

Answer:

0.02896 kg/s

Explanation:

A_1 = Initial displacement = 0.5 m

A21 = Final displacement = 0.1 m

t = Time taken = 0.5 s

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Displacement is given by

x=Ae^{-\dfrac{b}{2m}t}cos(\omega t+\phi)

At maximum displacement

cos(\omega t+\phi)=1

\\\Rightarrow A_2=A_1e^{-\dfrac{b}{2m}t}\\\Rightarrow \dfrac{A_1}{A_2}=e^{\dfrac{b}{2m}t}\\\Rightarrow ln\dfrac{A_1}{A_2}=\dfrac{b}{2m}t\\\Rightarrow b=\dfrac{2m}{t}\times ln\dfrac{A_1}{A_2}\\\Rightarrow b=\dfrac{2\times 0.045}{5}\times ln\dfrac{0.5}{0.1}\\\Rightarrow b=0.02896\ kg/s

The magnitude of the damping coefficient is 0.02896 kg/s

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