Mass of the block = 1.4 kg
Weight of the block = mg = 1.4 × 9.8 = 13.72 N
Normal force from the surface (N) = 13.72 N
Acceleration = 1.25 m/s^2
Let the coefficient of kinetic friction be μ
Friction force = μN
F(net) = ma
μmg = ma
μg = a
μ =
μ =
μ = 0.1275
Hence, the coefficient of kinetic friction is: μ = 0.1275
Answer: A)
Explanation:
The equation for the moment of inertia of a sphere is:
(1)
Where:
is the moment of inertia of the planet (assumed with the shape of a sphere)
is the mass of the planet
is the radius of the planet
Isolating from (1):
(2)
Solving:
(3)
Finally:
Therefore, the correct option is A.
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that force on the passenger while moving in circle is given as
now variation in force is given as
here speed is constant
Part b)
Now if the variation in force is required such that r is constant then we will have
so we have
Part c)
As we know that time period of the circular motion is given as
so here if radius is constant then variation in time period is given as