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Reil [10]
3 years ago
6

What is the cell wall & the chloroplasts?

Chemistry
1 answer:
adoni [48]3 years ago
6 0

The cell wall is mixed with the cell membrane, the cell wall is outside of the membrane and the cell membrane is letter i which allows materials to pass in and out of the cell.

Chloroplasts are letter k they basically just help the plant use photosynthesis.

cell wall: f

chloroplasts: k

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What is it called when an enzyme changes shape
7nadin3 [17]

Answer: Induced Fit

Explanation: The process wherein the enzymes change their shape is called as induced fit. It is the precision aligning of enzymes essential for catalytic activity which is caused by the binding of the substrate as enzymes possess active sites. Hence, as the substrate approaches the enzymes, the enzyme alters its shape.

4 0
2 years ago
Common brass is a copper and zinc alloy containing 37.0% zinc by mass and having a density of 8.48g/cm3. A fitting composed of c
inysia [295]
First, we calculate the mass of the sample:

mass = density x volume
mass = 8.48 x 112.5
mass = 954 grams

Now, we will calculate the mass of each component using its percentage mass, then divide it by its atomic mass to find the moles and finally multiply the number of moles by the number of particles in a mole, that is, 6.02 x 10²³.

Zinc mass = 0.37 x 954
Zinc mass = 352.98 g
Zinc moles = 352.98 / 65
Zinc moles = 5.43
Zinc atoms = 5.43 x 6.02 x 10²³
Zinc atoms = 3.27 x 10²⁴

Copper mass = 0.63 x 954
Copper mass = 601.02 g
Copper moles = 601.02 / 64
Copper moles = 9.39
Copper atoms = 9.39 x 6.02 x 10²³
Copper atoms = 5.56 x 10²⁴
3 0
3 years ago
Convert the following<br> 4. 100 cm =<br> 5. 453 m = _<br> 6. 89847nm = _<br> 7. 3Mm =
fredd [130]
4. I meter
5. 0.453 kilometers
6. 89.84700 microns
7. Yo momma
6 0
3 years ago
Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con
erik [133]

Explanation:

The given data is as follows.

         Thickness (dx) = 0.87 m,       thermal conductivity (k) = 13 W/m-K

        Surface area (A) = 5 m^{2},       T_{1} = 14^{o}C

        T_{2} = 93^{o}C

According to Fourier's law,

                    Q = -kA \frac{dT}{dx}

Hence, putting the given values into the above formula as follows.

                      Q = -kA \frac{dT}{dx}

                          = -13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}

                          = 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

4 0
3 years ago
What is the final temperature when 60.2 g of water at 72.4°C is mixed with 20.3 g of water at 34.4°C? (The specific heat of wate
Murljashka [212]

Answer:

72.3 c

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5 0
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