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3 years ago

Find the critical value tc for the confidence level cequals 0.95 and sample size nequals 19.

1 answer:

8 0

The critical values are fixed values which can be obtained from the standard t crit tables. We can find the critical value tc when the degrees of freedom and confidence level are given. The degrees of freedom is simply:

Degrees of Freedom = Number of samples – 1

Degrees of Freedom = 19 – 1

Degrees of Freedom = 18

From the t critical tables, the tc corresponding to Degrees of Freedom equal to 18 and Confidence level equal to 95% is as follows:

tc = 2.101

Therefore this means that any t value beyond 2.101, we already reject the null hypothesis.

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Given no other restrictions, what are the domain and range of the following function?

balandron [24]

Domain is: D = all real numbers

and Range is: R = {y | y > 0}

Option C is correct.

Step-by-step explanation:

We are given a function $f(x) = x^2 - 2x + 1$ and we need to find domain and range of this function

Domain:

The domain of a function is the set of points for which the function is real and defined.

Since all the values give the result which is real and defined so domain is all real numbers.

Range:

The set of values of the variable that is dependent, the function should be defined.

So, all the values should be greater than 0 i.e {y | y > 0}

So, Domain is: D = all real numbers

and Range is: R = {y | y > 0}

Option C is correct.

Keywords: Domain and Range

Learn more about Domain and Range at:

#learnwithBrainly

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3 years ago

True or False: An isosceles trapezoid is a trapezoid.

svlad2 [7]

Answer:

I think the answer is True

Step-by-step explanation:

(^///^)

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3 years ago

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What is six plus two

maksim [4K]

Answer:

the correct answer is eight

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3 years ago

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The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

nevsk [136]

Answer:

1052

Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is