All categories

3 years ago

Which is the best reason why 3/5 is the exact quotient for 1/2÷5/6

Mathematics

1 answer:

romanna [79]3 years ago

4 0

Because when divided a fraction u must flip a fraction and cross multiply
1/2÷5/6
1/2×6/5
3/5

You might be interested in

A rectangular prism has a base area of 2 square feet and a height of 5 feet. What

kvasek [131]

11 cubic feet is the answer

8 0

3 years ago

A can of apple juice contains 175 calories per 2.5 servings at this rate how many calories are in 4 servings

user100 [1]

Uhmmm i lost the answer while doing this

8 0

3 years ago

Read 2 more answers

Write the linear equation that gives the rule for this table.

MAVERICK [17]

Answer:

The linear equation that gives the rule for this table will be:

y=x+25

Step-by-step explanation:

Taking two points from the table

(2, 27)

(3, 28)

Finding the slope between two points

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(2,\:27\right),\:\left(x_2,\:y_2\right)=\left(3,\:28\right)$

$m=\frac{28-27}{3-2}$

$m=1$

We know the slope-intercept form of linear equation is

$y=mx+b$

where m is the slope and b is the y-intercept

substituting the point (2, 27) and m=1 in the slope-intercept form to determine the y-intercept 'b'

$y=mx+b$

27 = 1(2)+b

27-2 = b

b = 25

Now, substituting m=1 and b=25 in the slope-intercept form to determine the linear equation

y=mx+b

y=1(x)+25

y=x+25

Thus, the linear equation that gives the rule for this table will be:

y=x+25

4 0

3 years ago

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the <u>distance formula</u>.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$