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3 years ago

Is the gravity a black hole strong enough to keep light from escaping True or False

Chemistry

1 answer:

puteri [66]3 years ago

4 0

Answer:

The gravitational pull of a black hole is so strong that nothing, not even light, can escape once it gets too close. ... Moving at close to the speed of light, these particles ricochet off the event horizon and get hurled outward along the black hole's axis of rotation

(True)

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2Fe + 6HCl -> 2FeCl3 + 3H2 If 7.0 moles of HCl is added to enough iron that the HCl is completely used up, how many

DENIUS [597]

Answer: 3.5 moles of hydrogen gas will be produced.

Explanation:

The balanced chemical equation is:

$2Fe+6HCl\rightarrow 2FeCl_3+3H_2$

As HCl gets completely used up, $HCl$ is the limiting reagent.

According to stoichiometry :

6 moles of $HCl$ produces = 3 moles of $H_2$

Thus 7.0 moles of $HCl$ produces= $\frac{3}{6}\times 7.0=3.5moles$ of $H_2$

Thus 3.5 moles of hydrogen gas will be produced.

3 0

3 years ago

If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff

sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , $F=\mu_kN$ ( here $\mu_k$ is coefficient of kinetic friction and N is normal force)

Therefore, $\mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k$

Now, both forces are equal.

$122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26$

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0

4 years ago

Arrange the following compounds in the order of increasing reactivity toward nucleophilic acyl substitution, with least reactive

lutik1710 [3]

Answer:

The correct order of increasing reactivity toward nucleophilic acyl substitution is E < D < C < A < F < B.

Explanation:

The stability of the leaving group best determines the manner of reactivity of carboxylates to nucleophilic substitution after the substitution of the nucleophile to the leaving group. The leaving group should, therefore, be protonated with hydrogen ion in the solution to form a stable molecule. From the given list: The leaving group for A, Ethyl thioacetate will be ethanethiol. For B, Acetyl chloride will be Hydrochloric acid. For C, Sodium acetate will be Sodium Hydroxide. For D, Ethyl acetate will be Ethanol. For E, Acetamide will be Ammonia, and for F, Acetic anhydride will be Ethanoic acid. The reactivity of the substitution reaction is dependent on the stability of these leaving groups. The stability of these leaving groups depends on their pKa, and the more the pKa, the lesser the acidity of the leaving group, and the lower the reactivity. Therefore, considering their pKa: A is 8.5, B is -7, C is 13.8, D is 15.9, E is 36, and F is 4.8. When we rearrange this pKa in descending order, we have E, D. C, A, F, B. Which is also the increased reactivity of the nucleophilic acyl substitution.

5 0

3 years ago

Which substance is a primary source of hydrocarbon

IceJOKER [234]

Answer:

Hydrocarbons are molecules consisting of both hydrogen and carbon. They are most famous for being the primary constituent of fossil fuels, namely natural gas, petroleum, and coal. For this reason, fossil fuel resources are often referred to as hydrocarbon resources.Jun 25, 2018

https://energyeducation.ca ›

6 0

3 years ago

Which of the following terms refers to the area immediately around the eye

Anit [1.1K]

Answer:

the eye socket

Explanation:

the area around the eye is called the eye socket or the eye orbit.

5 0

3 years ago