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Elanso [62]
2 years ago
5

the answer choices for all are shifts to the right, shifts to the left, and no change I need help plsssss

Chemistry
1 answer:
GenaCL600 [577]2 years ago
8 0
Do you still need the answer for these ? if so , i have them
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PLEASE HELP ME ASAP I WILL MARK BRAINLYEST AND I WILL ALSO GIVE 5 EXTRA POINTS
sdas [7]

Answer:

Jack Beacuse...

Explanation:

the soil has water in it so it will be more than one matterial

5 0
2 years ago
Read 2 more answers
What is the molarity of 2.00 L of a solution that contains 14.6 g NaCl?
White raven [17]

Answer: The molarity of the solution is 0.125 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of NaCl = \frac{\text {given mass}}{\text {Molar mass}}=\frac{14.6g}{58.5g/mol}=0.250mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.250mol}{2.00L}=0.125M

Therefore, the molarity of the solution is 0.125 M

8 0
3 years ago
A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.
adell [148]

Answer:

a) V=4.3x10^3mL

b) V=4.3x10^6mm^3

c) \rho=1.5x10^5g/L

Explanation:

Hello,

a) In this case, the given height in cm is:

h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm

And the radius in cm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL

b) In this case, the given height in mm is:

h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm

And the radius in mm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm

Thus, the volume in cubic millimeters is:

V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\   \\\rho=1.5x10^5g/L

Best regards.

8 0
3 years ago
In 0.4 mole of H2S, how many atoms of H are there? ​
Debora [2.8K]

Answer:

8

Explain

H: Ignoring the coefficient, we know there's 5+3=8 atoms

5 0
2 years ago
Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota
Shalnov [3]

Answer:

1. 10.6\; \rm m (one decimal place.)

2.0.79\; \rm g (two decimal places.)

3. 16.5\;\rm cm^2 (three significant figures.)

Explanation:

<h3>1.</h3>

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

  • 5.6792\;\rm m has four decimal places.
  • 0.6\; \rm m has only one decimal place.
  • 4.33\; \rm m has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: \rm m.)

Therefore:

\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m. (Rounded to one decimal place.)

<h3>2.</h3>

Similarly:

  • \rm 3.70\; \rm g has two decimal places.
  • 2.9133\; \rm g has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be \rm g (same as the unit of the two inputs.)

\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g. (Rounded to two decimal places.)

<h3>3.</h3>

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

  • 4.51\; \rm cm has three significant figures.
  • 3.6666\; \rm cm has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be \rm cm \cdot cm, which is occasionally written as \rm cm^2.

\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2. (Rounded to three significant figures.)

7 0
3 years ago
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