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3 years ago

Explain Gay-Lussac’s Law in terms of the kinetic-molecular theory.

Chemistry

1 answer:

viktelen [127]3 years ago

7 0

Answer:

Gay-Lussac's law states that in a closed system of fixed volume, as the temp and the pressure of the gas increases.

Explanation:

Temperature is a measure of the average kinetic energy of a substance. As the temp of a substance rises, its molecules are moving faster

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Draw conclusion: The density of water is 1.0 g/mL, or 1.0 g/cm². Look at the data in your table. How can you use the density of

ANEK [815]

Answer:

work out if it's either going to sink or float

Explanation:

this can be carried out by calculating the numbers

3 0

3 years ago

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago

What is the mass of 2.23 × 10^23 atoms of aluminum?

rjkz [21]

Answer:

Explanation:

In image

Take atomic mass or molar mass

of Al =27

7 0

3 years ago

What element in the second period has the largest atomic radius?

Allushta [10]

Answer:

Na is the element from the second period that has the largest atomic radius

Explanation:

The atomic radius is a chemist property from the periodic table. It is decreased when we move in a period from the periodic, so the element in the second period that has the largest radius is Na, and the shortest, the Ar

The atomic radius indicates the distance between the nucleus and the outermost valence layer. In the periods it decreases with increasing Atomic Number, to the right, due to the attraction that the nucleus exerts on the electrons of the outermost orbitals, thus decreasing the core-electron distance.

3 0

3 years ago

If 0.213 moles of argon occupies a volume of 652 mL at a particular temp and pressure, what volume would it occupy if 0.162 mole

Andreas93 [3]

Answer:

V₂ = 495.89 mL

Explanation:

Given data:

Initial number of moles = 0.213 mol

Initial volume = 652 mL

Final number of moles = 0.162 mol

Final volume = ?

Solution:

V₁/n₁ = V₂/n₂

By putting values,

652 mL/0.213 mol = V₂ /0.162 mol

V₂ = 652 mL 0.162 mol /0.213 mol

V₂ = 105.62 mL.mol /0.213 mol

V₂ = 495.89 mL

3 0

3 years ago