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valentinak56 [21]
3 years ago
14

Explain Gay-Lussac’s Law in terms of the kinetic-molecular theory.

Chemistry
1 answer:
viktelen [127]3 years ago
7 0

Answer:

Gay-Lussac's law states that in a closed system of fixed volume, as the temp and the pressure of the gas increases.

Explanation:

Temperature is a measure of the average kinetic energy of a substance. As the temp of a substance rises, its molecules are moving faster

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Substance
ipn [44]

Answer:

lithium 3

Explanation:

This is because lithium has three protons

6 0
3 years ago
What element is reduced in the following reaction?
riadik2000 [5.3K]
 the oxidation states of the elements before and after the reaction is;
Pb oxidation state changes from 0 to +2
SO₄²⁻ ion there's no change in the oxidation state during the reaction
Au oxidation state changes from +3 to 0
reduction reactions are when there's a decrease in the oxidation state of the species 
oxidation reactions are when theres an increase in the oxidation state of the species 
the element where there's a decrease in oxidation state is Au. 
Therefore Au gets reduced.
answer is B) Au
6 0
3 years ago
Why does the mass number for an element differ from the average atomic mass for the element?​
yarga [219]

Answer:

the mass number is the number of protons and neutrons added and the average atomic mass is the weight of the protons and neutrons

4 0
3 years ago
Aqueous hydrochloric acid reacts with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . If of water i
Kaylis [27]

Answer:

87.9%

Explanation:

Balanced Chemical Equation:

HCl + NaOH = NaCl + H2O

We are Given:

Mass of H2O = 9.17 g

Mass of HCl = 21.1 g

Mass of NaOH = 43.6 g

First, calculate the moles of both HCl and NaOH:

Moles of HCl: 21.1 g of HCl x 1 mole of HCl/36.46 g of HCl = 0.579 moles

Moles of NaOH: 43.6 g of NaOH x 1 mole of NaOH/40.00 g of NaOH = 1.09 moles

Here you calculate the mole of H2O from the moles of both HCl and NaOH using the balanced chemical equation:

Moles of H2O from the moles of HCl: 0.579 moles of HCl x 1 mole of H2O/1 mole of HCl = 0.579 moles

Moles of H2O from the moles of NaOH: 1.09 moles of HCl x 1 mole of H2O/1 mole of NaOH = 1.09 moles

From the calculations above, we can see that the limiting reagent is HCl because it produced the lower amount of moles of H2O. Therefore, we use 0.579 moles and NOT 1.09 moles to calculate the mass of H2O:

Mass of H2O: 0.579 moles of H2O x 18.02 g of H2O/1 mole of H2O = 10.43 g

% yield of H2O = actual yield/theoretical yield x 100= 9.17 g/10.43 g x 100 = 87.9%

3 0
3 years ago
When placed in H2O, a sodium pellet catches on fire as hydrogen gas is liberated and sodium hydroxide forms.
tangare [24]
I this is really hard who can help me complete all of these because this is acknowledged
3 0
3 years ago
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