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2 years ago

Topics on how humans use energy pls can somebody give me a few..

Chemistry

1 answer:

kupik [55]2 years ago

5 0

Answer: Humans use energy to carry out their daily activities, like moving around, working, running etc.

Explanation:

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Why does changing the volume of a container change the pressure of the gas in it?

klio [65]

Changing the volume increases the area that the molecules collide with so the force is spread over a larger area.

6 0

3 years ago

Read 2 more answers

PLEASE HELP!!!

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

8 0

2 years ago

How are concentration and chemical reaction rate related?

dem82 [27]

Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

Explanation:

7 0

3 years ago

C + 2H2 -> CH4

ankoles [38]

Answer:

C) 4

Explanation:

The reaction :

C (s) + 2H₂ (g) ⇒ CH₄ (g)

12g 4g 16g

Hence, based on this we can say that : 2 moles of hydrogen gas are needed to produce 16g of methane.

For 32g of methane

Number of moles of H₂ = 32/16 × 2
Number of moles of H₂ = 4

4 0

2 years ago

Read 2 more answers

Sample A: 300 mL of 1M sodium chloride

yarga [219]

Answer:

sample B contains the larger density

Explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

$C = \frac{moles \ of \ solute, \ mol}{liters \ of \ solvent} \\\\Moles \ of \ solute \ for \ sample \ A = 1 \times 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 \times 0.145 = 0.2175 \ mol$

The reacting mass for sample A = 0.3mol x 58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A $= \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L$

The density of sample B $= \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L$

Therefore, sample B contains the larger density

5 0

3 years ago