Ian picked 5 times as many strawberries as Michelle. Joe picked 7 times as many strawberries as Michelle. Ian and Joe picked a t
1 answer:
You might be interested in
Answer:
(f +g)(2) = -7
Step-by-step explanation:
Functions are added by adding their values.
<h3>Application</h3>(f +g)(2) = f(2) +g(2)
= (2 -8) +(4(2) -9) . . . . . evaluate f and g with z=2
= -6 +(-1)
(f +g)(2) = -7
Answer:
(a) The mean number of minutes of daily activity of the 6 mildly obese people exceeds 420 minutes is 0.0495.
(b) The mean number of minutes of daily activity of the 6 lean people exceeds 420 minutes is 0.9909.
Step-by-step explanation:
Let <em>X</em> = amount of time mildly obese people do daily activity and <em>Y</em> = amount of time lean people do daily activity.
The random variable and
.
The sample size of mildly obese and lean people selected is, <em>n</em> = 6.
(a)
Compute the probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 420 minutes as follows:
*Use the <em>z</em>-table for the probability.
Thus, the mean number of minutes of daily activity of the 6 mildly obese people exceeds 420 minutes is 0.0495.
(b)
Compute the probability that the mean number of minutes of daily activity of the 6 lean people exceeds 420 minutes as follows:
*Use the <em>z</em>-table for the probability.
Thus, the mean number of minutes of daily activity of the 6 lean people exceeds 420 minutes is 0.9909.