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3 years ago

One of the driving forces of atmospheric circulation is

1 answer:

5 0

Convention is known as one of the driving forces of atmospheric circulation. Convection is defined as the heat transfer due to bulk movement of the molecules within fluids like liquids and gases, uncluding th molten rock. Convention takes place through diffusion, advection or can be both and it is usually a domination form of heat that transfer into liquids and gases.

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Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the

Dafna11 [192]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Heat capacity of body 1 :

$\qquad \sf \dashrightarrow \:m_1s_1$

Heat capacity of body 2 :

$\qquad \sf \dashrightarrow \:m_2s_2$

it's given that, the the head capacities of both the objects are equal. I.e

$\qquad \sf \dashrightarrow \:m_1s_1 = m_2s_2$

$\qquad \sf \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1}$

Now, consider specific heat of composite body be s'

According to given relation :

$\qquad \sf \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2$

$\qquad \sf \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}$

$\qquad \sf \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }$

[ since, $m_2s_2 = m_1s_1$ ]

$\qquad \sf \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}$

$\qquad \sf \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}$

$\qquad \sf \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}$

$\qquad \sf \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2}$

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6 0

3 years ago

Read 2 more answers

Complete the sentence to describe what a wave is and what it does. A wave is a disturbance that carries from one place to anothe

kozerog [31]

Answer:

Energy

A wave is a disturbance that carries energy from one place to another through matter and space.

Explanation:

A wave can be defined as a form of disturbance that carries energy from one place to another through matter and space.

The energy of wave depends on the frequency of the wave and the wavelength (lambda) of that particular wave.

Mathematically,

V = f × lambda

5 0

4 years ago

Read 2 more answers

starting from rest a skateboarder accelerates at a rate of 2 [m/s 2] for 2 [s]. what is their speed afterwards?

N76 [4]

Answer:

sorry I don't know I am too bad a t this coz I am only at class 7

7 0

2 years ago

A stunt driver wants to make his car jump over 8 cars parked side by side below a horizontal ramp.

Genrish500 [490]

<u>Answer:</u>

a) Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

<u>Explanation:</u>

a) The height of ramp = 1.5 meter

Horizontal distance he must clear = 22 meter

The car is having horizontal motion and vertical motion. In case of vertical motion the acceleration on the car is acceleration due to gravity.

We have equation of motion, $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In case of vertical motion initial velocity = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate time when displacement = 1.5 meter.

$1.5=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 0.553 seconds$

So the car has to cover a distance of 22 meter in 2.119 seconds.

So minimum speed required = 22/0.553 = 39.78 m/s

Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) When the take of angle is 7⁰ the vertical speed of car is not zero = V sin 7 = 0.122 V

So the in case of vertical motion we have initial velocity = 0.122 V, S = -1.5 meter( below ramp), acceleration = -9.8 $m/s^2$

Substituting

$-1.5=0.122V*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-0.122Vt-1.5=0$

In case of horizontal motion

Horizontal speed of car = V cos 7 = 0.993V

So it has to travel 22 meter in t seconds

0.993Vt = 22, Vt = 22.155 m

Substituting in the equation $4.9t^2-0.122Vt-1.5=0$

We will get $4.9t^2-0.122*22.155-1.5=0\\ \\ t = 0.926 seconds$

Speed required = 22.155/0.926 = 23.93 m/s

Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

7 0

4 years ago

A jet aircraft is traveling at 262 m/s in horizontal flight. The engine takes in air at a rate of 85.9 kg/s and burns fuel at a

Fittoniya [83]

Answer:

$F_T=60132.52N$

$P=15814852.76W$

Explanation:

From the question we are told that

Velocity of aircraft $V=263m/s$

Engine air intake rate $\triangle M_a=85.9kg/s$

Fuel burn rate $\triangle M_f =3.92kg/s$

Velocity of exhaust gas $V_e =921m/s$

Generally the Mass change rate of Rocket is mathematically given by

$\triangle M = \triangle M_a+\triangle M_f$

$\triangle M= 85.9+3.92$

$\triangle M=89.82kg/s$

Generally the Trust of the rocket is given mathematically by

$F_T=(\triangle M *V_e)-(dM_a/dt)*(V)$

$F_T=(89.82 *921)-(85.9)*(263)$

$F_T=60132.52N$

Generally the Rocket's delivered power is mathematically given by

Delivered power P

$P=V*F_T$

$P=263*60132.52N$

$P=15814852.76W.$

8 0

3 years ago