Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student
Answer:
Sry but the question is not visible.......so plzz attach another image
Answer:
0.00384 kg/m
Explanation:
The fundamental frequency of string waves is given by
For some tension (F) and length (L)
Fundamental frequency of G string
Fundamental frequency of E string
Linear mass density of E string is
So,
The linear density of the G string is 0.00384 kg/m
The temperature of the gas doubles while the density will remain the same. therefore the correct answer is C.
The gas equation is given as
PV=mRT \\
or\ P\propto T\ \ (\text{at}\ \text{constant}\ \text{volume)}
Therefore when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.
However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.
