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2 years ago

Is this enough money for this question

2 answers:

7 0

Answer:

36

Explanation:

Sex cells are different from body cells. Sex cells are made up of haploid number of cells. A haploid cell is half the original number of cell. When sex cell combines, they fuse and unite the half number of cells to form a single diploid which makes a complete body cell by a series of process.
All sex cells only contains half the number of cells in their parent.

DiKsa [7]2 years ago

3 0

Answer:

The answer is 36 on edgenuity.

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Convert 1.500 L to cm3. To the correct number of significant figures.

Tasya [4]

Answer:

1500 cubic centimeters or cm^3

Explanation:

1 liter is 1000 cm^3

move the decimal 3 places to right

8 0

1 year ago

Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) -7.3

Andreyy89

Answer:

The pump work is 3451 kJ/s

Explanation:

Pump work (W) is calculated as

$W = (h_f - h_i) \times \dot{m}$

where

$h_f$ is the enthalpy of water at its final state

$h_i$ is the enthalpy of water at its initial state

$\dot{m} = 10 kg/s$ is water mass flow

For liquids, properties are evaluated as saturated liquid. From the figure attached, it can be seen that

$h_f = 762.81 kJ/kg$

$h_i = 417.46 kJ/kg$

Replacing

$W = (762.81 kJ/kg - 417.46 kJ/kg) \times 10 kg/s$

$W = 3451 kJ/s$

8 0

3 years ago

In a titration experiment, 31.4 mL of 1.120 M HCOOH is neutralized by 16.3 mL of Ba(OH)2. What is the concentration of the Ba(OH

11Alexandr11 [23.1K]

Answer : The concentration of the $Ba(OH)_2$ solution is, 2.16 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCOOH$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ba(OH)_2$ .

We are given:

$n_1=1\\M_1=1.120M\\V_1=31.4mL\\n_2=2\\M_2=?\\V_2=16.3mL$

Putting values in above equation, we get:

$1\times 1.120M\times 31.4mL=2\times M_2\times 16.3mL\\\\M_2=2.16M$

Thus, the concentration of the $Ba(OH)_2$ solution is, 2.16 M

7 0

3 years ago

The tabulated data were collected for this reaction:

erastovalidia [21]

Answer:

ai) Rate law, $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

aii) Rate constant, k = 1.25

b) Overall order of reaction = 1.5

Explanation:

Equation of Reaction:

$CH_{3} Cl (g) + 3 Cl_2 (g) \rightarrow CCl_4 (g) + 3 HCl (g)$

If $A + B \rightarrow C + D$ , the rate of backward reaction is given by:

$Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$

k is constant for all the stages

Using the information provided in lines 1 and 2 of the table:

$0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1$

Using the information provided in lines 3 and 4 of the table and insering the value of a:

$0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\$

$0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5$

The rate law is: $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

The rate constant $k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$ then becomes:

$k = 0.014 / ( [0.050] [0.050]^(0.5) )\\k = 1.25$

b) Overall order of reaction = a + b

Overall order of reaction = 1 + 0.5

Overall order of reaction = 1.5

3 0

2 years ago

Is a hollow tube that serves as passageway of air into the luns

KIM [24]

Answer:

The air that we breathe in enters the nose or mouth, flows through the throat (pharynx) and voice box (larynx) and enters the windpipe (trachea). The trachea divides into two hollow tubes called bronchi

Explanation:

7 0

2 years ago