Answer:
Explanation:
The period of oscillation is given as
T=2π√m/k
Making k subject of the formula
Square both sides of the equation
T²=4π²(m/k)
Cross multiply
T²k=4π²m
Then, divide through by T²
k=4π²m/T²
Where
k is spring constant
m is the mass of the bob
And T is the period of the oscillation
m=140g=0.14kg
14 oscillations takes 14 seconds
Then the period is
T=time/oscillation
T=14/14
T=1sec
Then,
k=4π²m/T²
k=4π²×0.14/1²
k=1.76N/m
Then, the spring constant is 1.76N/m
a physical change occurs when materials change shape or size but not the molecular composition of the substance
Answer:43.311 J
Explanation:
Given
mass of frame
mass of wheel
radius of wheel
v=3.22 m/s
Moment of inertia of each wheel\left ( I\right )=\frac{1}{2}mr^2[/tex]
kinetic Energy of whole cycle=Kinetic energy of wheels and frame+rotational energy of Wheels
K.E.=39.037+4.274=43.311J
Answer:
Ball A will move towards West with speed 8 m/s
Ball B will move towards East with speed 12 m/s
Explanation:
As we know that during collision there is no external force on the system
So here we can use momentum conservation for finding the final velocities of two balls
so we have
since two balls are identical so we have
also we know that for elastic collision we have
so we have
so we have
Towards East
Towards West
Answer:
Explanation:
Remark
At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.
Givens
h = 20 m
hd = 60 m
g = 9.81
vi = 0
Formula
d = vi*t + 1/2 a * t^2 We are solving for t
Solution
When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters
d = 0*t + 1/2 * 9.81 a* t^2
20 = 4.91 * t^2 Divide by 4.91
20/4.91 = 4.91 t^2 / 4.91
4.073 = t^2 Take the square root of both sides.
t = 2.02 seconds
Horizontal
d = 60 m
t = 2.02 seconds
v = ?
Note: there is no horizontal deceleration or acceleration
v = d/t
v = 60/2.02
Answer: v = 29.73 m/s