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lesya [120]
3 years ago
13

Suppose a container holds 1000 hydrogen molecules and 1000 oxygen molecules that react to form water. how many water molecules w

ill be left in the container?
Physics
1 answer:
Murrr4er [49]3 years ago
6 0

The reaction is:

H_{2} +  \frac{1}{2} O_{2} =  H_{2}O

From the equation, he limiting reactant is the oxygen. Assuming 100% yield, all of the oxygen must react to form water.

1000 mol O_{2} * (1 mol H_{2}O ÷ ½ mol O_{2}) = 2000 moles water produced

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A father racing his son has 1/4 the kinetic energy of the son, who has 1/3 the mass of the father. The father speeds up by 1.2 m
sergejj [24]

Answer:

Explanation:

KE_s: Kinetic Energy Son

KE_f: Kinetic Energy Father.

Relationship

KE_f: =  (1/4) KE_s

m_s: = (1/3) m_f

v_f: = velocity of father

v_s: = velocity of the son

Relationship

1/2 mf (v_f + 1.2)^2 = 1/2 m_s (v_s)^2      Multiply both sides by 2.

mf (v_f + 1.2)^2 = m_s * (v_s)^2               Substitute for the mass of the m_s

mf (v_f + 1.2)^2 = (m_f/3) * (v_s)^2         Divide both sides by father's mass

(v_f + 1.2)^2 = 1/3 * (v_s)^2                      multiply both sides by 3

3*(v_f + 1.2)^2 = (v_s) ^2                         Take the square root both sides

√3 * (v_f + 1.2) = v_s

Note

  • You should work your way through all the cancellations to find the last equation shown about
  • We have another step to go. We have to use the first relationship to get the final answer.

KE_f = (1/4) KE_s                                                  Multiply by 4

4* KE_f = KE_s                                                     Substitute (again)

4*(1/2) m_f (v_f + 1.2)^2 = 1/2* (1/3)m_f *v_s^2   Divide by m_f

2* (v_f + 1.2)^2 = 1/6 * (v_s)^2                              multiply by 6

12*(vf + 1.2)^2 = (v_s)^2                                        Take the square root

2*√(3* (v_f + 1.2)^2) = √(v_s^2)

2*√3 * (vf + 1.2) = v_s

Use the second relationship to substitute for v_s so you can solve for v_f

2*√3 * ( v_f + 1.2) = √3 * (v_f + 1.2)                     Divide by sqrt(3)

2(v_f + 1.2) = vf + 1.2

Edit

2vf + 2.4 = vf + 1.2

2vf - vf + 2.4 = 1.2

vf = 1.2 - 2.4

vf = - 1.2

This answer is not possible, but 2 of us are getting the same answer. The other person is someone whose math I would never question. She rarely makes an error. And I do mean rarely. Could you check to see that you have copied this correctly?

5 0
4 years ago
Which best describes a parallel circuit?
yarga [219]

c more than 1 pwy..................

8 0
4 years ago
Tlo
kondor19780726 [428]

Answer:

9.949 m

Explanation:

From the question,

L' = L+LαΔT................. Equation 1

Where L' = New length, L = Original length, α = linear expansivity of Cu, ΔT = change in temperature

Given: L = 10 m, α  = 0.00017 K⁻¹, ΔT = 50-80

L' = 10+10(0.00017)(50-80)

L' = 10-0.051

L' = 9.949 m

Hence the new legth of Cu is  9.949 m

5 0
3 years ago
For those who think electric cars are sissy, Keio University in Japan has tested a 22-ft long prototype whose eight electric mot
Kruka [31]

Answer:

The percent of power extended against sea-level air drag is 50.15%

Explanation:

Length L is 22 ft, Power P is 590 hp,

Speed of air V = 175 mi/h. To convert to ft, we will multiply by 1.46

V = 175 × 1.46 = 255.5 ft

Frontal Area A is given as 23.5 ft

Coefficient of drag, Cd is 0.35

From text, Density of Air at sea level ρ = 0.00237 slug/ft³

The formula for calculating Drag Force F is

F = Cd × \frac{1}{2} × ρAV²

Substitute the values above into the formula

F = 0.35 × \frac{1}{2} × 0.00237 × 23.5 × 255.5²

= 0.35 × \frac{1}{2} × 3635.78

= 636.26 lbf

But Power P = FV

Therefore we substitute for F and V to get P

P = 636.26 × 255.5

= 162564.43 ft.lbf/s

To convert to horsepower, we multiply by 0.00182 hp

= 162564.43 × 0.00182

= 295.87 hp

The percent of power extended against sea-level air drag is

= (295.87/590) × 100

= 50.15%

6 0
3 years ago
Read 2 more answers
A block of mass 8 m can move without friction
nekit [7.7K]

Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

F = M2 g     the net force accelerating the system

M2 g = (M1 + M2) a

a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2

5 0
2 years ago
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