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Alenkasestr [34]
3 years ago
10

A traves de una manguera de 1 in de diámetro fluye gasolina con una velocidad media de 5ft/s ¿cuál es el gasto?

Physics
1 answer:
jonny [76]3 years ago
6 0

Answer:

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

Explanation:

El gasto es el flujo volumétrico de gasolina (Q), medido en pies cúbicos por segundo, que sale de la manguera. Asumiendo que la velocidad de salida es constante, tenemos que el gasto a través de la manguera es:

Q = \frac{\pi}{4}\cdot D^{2}\cdot v (1)

Donde:

D - Diámetro de la manguera, medido en pies.

v - Velocidad medida de salida, medida en pies por segundo.

Si sabemos que D = \frac{1}{12}\,ft y v = 5\,\frac{ft}{s }, entonces el gasto de gasolina es:

Q = \frac{\pi}{4}\cdot \left(\frac{1}{12}\,ft \right)^{2} \cdot \left(5\,\frac{ft}{s} \right)

Q \approx 0.0273\,\frac{ft^{3}}{s}

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

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Answer:

True

Explanation:

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While that of resistors in parallel is the sum of the reciprocal of the resistance given as

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There is a set table of rate constants for the rate equation. True or false
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The given statement "There is a set table of rate constants for the rate equation" is true.

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Electrolytes serve several purposes in the body, including _________
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An object moving with a speed of 48 m/s has a kinetic energy of 4,632 J, what is the mass, in kg,
pickupchik [31]

Answer:

4.0 Kg

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

Kinetic energy can be defined as the energy possess by a moving object. Mathematically, it is expressed as:

KE = ½mv²

Where

KE => kinetic energy

m => mass of object

v => velocity

With the above formula, we can obtain the mass of the object as follow:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

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Divide both side by 1152

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Therefore, the mass of the object is 4.0 Kg

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