All categories

2 years ago

Water waves, earthquake waves, sound waves, and the waves that travel down a rope or spring are all examples of what waves.

Physics

1 answer:

Margaret [11]2 years ago

5 0

Compression waves :-)

You might be interested in

A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio

DanielleElmas [232]

Answer:

$\alpha =-2.2669642\times^{-10}rad/s^2$

Explanation:

Angular acceleration is defined by $\alpha =\frac{\Delta \omega}{\Delta t}=\frac{\omega_f-\omega_i}{\Delta t}$

Angular velocity is related to the period by $\omega=\frac{2\pi}{T}$

Putting all together:

$\alpha =\frac{\frac{2\pi}{T_f}-\frac{2\pi}{T_i}}{\Delta t}=\frac{2\pi}{\Delta t}(\frac{1}{T_f}-\frac{1}{T_i})$

Taking our initial (i) point now and our final (f) point one year later, we would have:

$\Delta t=1\ year=(365)(24)(60)(60)s=31536000
s$

$T_i=0.0786s$

$T_f=0.0786s+7.03\times10^{-6}s$

So for our values we have:

$\alpha =\frac{2\pi}{\Delta t}(\frac{1}{T_f}-\frac{1}{T_i})=\frac{2\pi}{31536000s}(\frac{1}{0.0786s+7.03\times10^{-6}s}-\frac{1}{0.0786s})=-2.2669642\times^{-10}rad/s^2$

Where the minus sign indicates it is decelerating.

8 0

3 years ago

Bádminton is played to a score of

Temka [501]

Badminton is played to a score of 21 points

4 0

2 years ago

Read 2 more answers

Study the diagram. Point C identifies the _____ of the wave.

Sonbull [250]

Answer:

Amplitude : The height of the wave from the origin to the crest/peak or trough

Explanation:

5 0

2 years ago

Read 2 more answers

What is the universe’s estimated age?

Amanda [17]

Answer:

13.77 Billion years old

Explanation:

4 0

2 years ago

Read 2 more answers

A ball droped from a building. How fast is it traveling after falling 3.55s

algol [13]

Answer:

d = 61.75 m

Explanation:

Given that,

A ball droped from a building.

We need to find how fast is it traveling after falling 3.55 s.

As it is dropped, its initial velocity is equal to 0.

Let d is the distance it covers after falling 3.55 s.

We can use second equation of motion to find d.

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a =g

$d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (3.55)^2\\\\d=61.75\ m$

So, it will cover 61.75 m after falling 3.55 seconds.

4 0

3 years ago