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pickupchik [31]
3 years ago
12

How do the sclera and the cornea compare?

Physics
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

The sclera focuses light that enters the eye, and the cornea controls how much light enters the eye.  

Explanation:

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What is the answer to this question number 2?
anzhelika [568]

Answer:

1⁺ ion

Explanation:

Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.

Most metals are electropositive and would prefer to lose electrons than to gain it.

Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.

On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.

3 0
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Which of the following is the best definition of vectors
Allisa [31]

A vector would be a quantity that has both magnitude and direction.

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According to the pressure-flow hypothesis, which of the following statements is not true?
adelina 88 [10]
"The movement of water into a nutrient-rich region of the phloem decreases the pressure in that region" is the statement that is not true according <span>to the pressure-flow hypothesis. The correct option among all the options that are given in the question is the fourth option or the last option. I hope it helps you.</span>
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Which feature of the ocean floor lies just off the beach and is a part of continental crust
4vir4ik [10]
The coastline/shoreline
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8 0
3 years ago
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A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

3 0
3 years ago
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