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djverab [1.8K]
3 years ago
5

A crate is sliding down an inclined ramp at a constant speed of 0.55 m/s. The vector sum of all the forces acting on this crate

must point down the ramp
Physics
1 answer:
Lemur [1.5K]3 years ago
8 0

Answer:

F_{net} = 0

Explanation:

here it is given that the crate is sliding down with constant speed

so we will have

v = constant

now we can say

a = \frac{dv}{dt}

so here we have

a = 0

now from Newton's II law we can say that sum of all forces on the system is always product of mass and its acceleration

so here we will have

F_{net} = ma

F_{net} = 0

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A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the condu
Artyom0805 [142]

3.60 A = 3.60 coulombs of charge per second

(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge

1 coulomb of charge is carried by 6.25 x 10^18 electrons

Number of electrons =

               (55.08 Coul) x (6.25 x 10^18 e/coul) = <em>3.4425 x 10^20 electrons</em>


7 0
4 years ago
You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,
g100num [7]

Answer:

T = 29.66 ^o C

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

ms \Delta T = m' L

so here we have

0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)

T = \frac{2512.5}{0.220 \times 385}

T = 29.66 ^o C

5 0
3 years ago
How many times does the world go around
sattari [20]
I'm not sure what you're asking but the earth has the ability to infinitely continue to spin or the earth completes 365.25 rotations during a full cycle. 
6 0
3 years ago
Whats the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s
Vesnalui [34]

Answer:

600J

Explanation:

1/2mv^2

1/2(12)(10^2)

6(100)

600

7 0
4 years ago
What is the gravitational force between a 45 kg person, and the Earth at 5.98 x 1024 kg, with a distance of
Assoli18 [71]

Answer:

C. 441 N

Explanation:

Gravitational force between two objects can by calculated by the formula

= G m₁m₂ / r² , m₁ and m₂ are masses at distance r

= ( 6.67 x 10⁻¹¹ x 45 x 5.98 x 10²⁴) / ( 6.38 x 10⁶ )²

= 44.09 x 10

= 440.9 N

= 441 N .  

7 0
3 years ago
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