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djverab [1.8K]
3 years ago
5

A crate is sliding down an inclined ramp at a constant speed of 0.55 m/s. The vector sum of all the forces acting on this crate

must point down the ramp
Physics
1 answer:
Lemur [1.5K]3 years ago
8 0

Answer:

F_{net} = 0

Explanation:

here it is given that the crate is sliding down with constant speed

so we will have

v = constant

now we can say

a = \frac{dv}{dt}

so here we have

a = 0

now from Newton's II law we can say that sum of all forces on the system is always product of mass and its acceleration

so here we will have

F_{net} = ma

F_{net} = 0

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Romashka-Z-Leto [24]

Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

7 0
2 years ago
Can you please help quick
Mademuasel [1]

Answer:

1. the difference between a series circuit and parallel are if a bulb goes out in a series circuit all go out and in a parallel if one goes out all the others stay on.

2. the function of a switch is to determine if the circuit is closed or open and how is stays on.

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3 years ago
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Relate the structure of water to its ability to act as a solvent
pishuonlain [190]

Explanation:

Water (H2O) as a polar covalent molecule has its arrangement of oxygen and hydrogen atoms where one end (hydrogen) has a partially positive charge while the other side (oxygen) had a partially negative charge.

It is also capable of forming hydrogen bonds with polar molecules. Each water molecule can form two hydrogen bonds involving their hydrogen atoms and two further hydrogen bonds using the hydrogen atoms attached to neighboring water molecules.

5 0
3 years ago
How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 45 j of work?
bija089 [108]

Here is your answer

5 coulomb

REASON :

We know that

Potential difference, V= W/q

where, W is work done

and, q is magnitude of charge

Given,

V= 9.0 v and W= 45 J

So,

using above relation, we get

9= 45/q

q= 45/9

q= 5 coulomb

HOPE IT IS USEFUL

6 0
3 years ago
The fulcrum of a uniform 20-kg seesaw that is 4.0 m long is located 2.5 m from one end. A 30-kg child sits on the long end. Part
uranmaximum [27]

Answer:

57 kg

Explanation:

Mass of seesaw = 20 kg

Length of seesaw = 4 m

Mass of child on the longer end = 30 kg

The weight of the seesaw acts at the center i.e. 2m

The algebraic sum of moments of all forces about any point is zero, hence, using the fulcrum as the reference point:

[x * 9.8* 1.5] - [20 * 9.8* (2.5 - 2)] - [30 * 9.8 * 2.5] = 0

=> 14.7x = (20*9.8*0.5) + 735

14.7x = 98 + 735

14.7x = 833

=> x = 833/14.7

x = 57 kg

7 0
3 years ago
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