Answer:
P₁ = 2.82 atm
Explanation:
Given data:
Initial volume = 28 L
Initial pressure = ?
Initial temperature = 65 °C (65 +273.15 = 338.15 K)
Final temperature = 35 °C (35 +273.15 = 308.15 K)
Final volume = 36 L
Final pressure = 2.0 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = P₂V₂T₁/T₂ V₁
P₁ = 2.0 atm × 36 L × 338.15 K / 308.15 K × 28 L
P₁ = 24346.8 atm .L. K / 8628.2 K.L
P₁ = 2.82 atm
Answer:
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The electrode A is a cathode. This is because it is negatively charged electrode and it attracts cations, or we can say it is positively charged.
The reaction occurs at the cathode
Zn2+ +2e⇒Zn
Anode reaction is
2CL- ⇒CL2+2e-
The overall reaction will be Zncl2(l) which completely disassociates then it is zn∧2+(l)+2cl∧-(l).
The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
brainly.com/question/26374513
THE ANSWER TO THE QUESTION IS A