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Scorpion4ik [409]
2 years ago
14

What volume in milliliters of 0.0180 M Ba(OH)₂ is required to neutralize 55.0 mL of 0.0500 M HCl?

Chemistry
1 answer:
Nataly_w [17]2 years ago
5 0

The volume in milliliters of 0.0180 M Ba(OH)₂ that is required to neutralize 55.0 mL of 0.0500 M HCl is 152.78mL.

<h3>HOW TO CALCULATE VOLUME?</h3>

The volume of a solution can be calculated by using the following expression:

C1V1 = C2V2

Where;

  • C1 = initial concentration
  • C2 = final concentration
  • V1 = initial volume
  • V2 = final volume

The volume can be calculated as follows;

0.0180 × V1 = 55 × 0.05

0.0180V1 = 2.75

V1 = 2.75 ÷ 0.0180

V1 = 152.78mL

Therefore, the volume in milliliters of 0.0180 M Ba(OH)₂ that is required to neutralize 55.0 mL of 0.0500 M HCl is 152.78mL.

Learn more about volume at: brainly.com/question/1578538

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Answer: Another useful feature of the periodic table is that most tables provide all the information you need to balance chemical reactions at a glance. The table tells each element's atomic number and usually its atomic weight. The typical charge of an element is indicated by its group.

Explanation:

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Do ionic compounds or covalent compounds conduct electricity
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None because Covalent compounds don’t conduct electricity because they are formed between the non metal atoms by sharing of electrons. The Covalent compounds haves no free electrons and also no ions and hence they do not conduct electricity. That is why they do not conduct electricity.

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3 years ago
If 97.7 ml of silver nitrate solution reacts with excess potassium chloride solution to yield 0.326 g of precipitate, what is th
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The complete balanced chemical reaction is written as:

AgNO3 + KCl ---> AgCl + KNO3 

where AgCl is our precipitate

 

So calculating for moles of AgCl produced: MM AgCl = 143.5 g/mol

moles AgCl = 0.326 g / (143.5 g/mol) = 2.27 x 10^-3 mol

we see that there is 1 mole of Ag per 1 mole of AgCl so:

moles Ag = 2.27 x 10^-3 mol

 

The molarity is simply the ratio of number of moles over volume in Liters, therefore:

Molarity = 2.27 x 10^-3 mol / 0.0977 L

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4 0
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Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?
Andre45 [30]

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06

6 0
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What happens when copper nitrate II is heated​
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Answer:

Copper nitrate is a blue coloured crystal.which copper nitrate is heated it loses the water molecule and then when is further heated it decomposes to give redddish brown gas,nitrogen dioxide and oxygen.

Explanation:

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