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weeeeeb [17]
3 years ago
12

A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant va

lue k. The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be _______
Physics
1 answer:
Temka [501]3 years ago
6 0

Answer: 2Mg/k

Explanation:

Let a be the extension experienced by the spring when a mass M is released from rest. And k is the force constant value

The potential energy lost by the mass is equal to that gained by the spring.

The potential energy lost by the mass = M x g x a

The energy gained by the spring = 1/2 x K x a^2

Therefore, M x g x a = 1/2 x K x a^2

Mga = Ka^2/2

2Mga = ka^2

Making a the subject of the formula,

Dividing through by a,

2Mg = ka

Therefore, a = 2Mg/k

The maximum extension produced in the length of the spring will be 2Mg/k.

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