Answer:
F = 120 N
Explanation:
Force x distance = energy
The bike has energy 1/2 . 80 . 6^2 = 1440 J
You are looking at an example of not reading the question properly.
Impulse = Force . time = change in momentum
F . 4 = 80 .6
F = 120 N
The object<span> is moving with a decreasing acceleration. The </span>object<span> is moving with </span>a constant<span> velocity.</span>
the resistance of the cable is 582.9 ohms
we are given the length of the cable which is 3 km, of 1.5 mm in, the diameter and resistivity of copper which is 1.72 m
The formula we are referring to for calculating the resistance of the cable is
R = ρl/A.
As there are 19 strands of copper conductors, so the resistance will be
R = 19( ρl/A)
Here ρ is the resisitivity = 1.72 , l is the length = 3(1+0.05)*10³3= 3150 m
A=pie/4(1.5 x 10⁻³)^2 =1.766 x 10⁻⁶ =1.766 x 10^-6
Substituting the values in the formula we get
R = 19 ( 1.72*3150 )/1.766 x 10⁻⁶
= 582.9 ohm
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Answer:
*******
Explanation:
is obviously the correct answer they are both so different yet so alike
The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).
- Work function is a material property defined as the minimum amount of energy required to infinitely remove electrons from the surface of a particular solid.
- The potential difference required to support all emitted electrons is called the stopping potential which is given by
.....(1) - where
is the stopping potential and e is the charge of the electron given by
.
It is given that work function (Ф) of monochromatic light is 2.50 eV.
Einstein photoelectric equation is given by:
....(2)
where K.E(max) is the maximum kinetic energy.
Substituting (1) into (2) , we get

As we know that
....(3)
where Speed of light,
and Planck's constant , 
From equation (3) , we get

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