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jekas [21]
3 years ago
15

12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley

Physics
1 answer:
atroni [7]3 years ago
7 0

Answer:

4 m/s

Explanation:

Momentum is conserved.

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

(50)(5) + (20)(1.5) = (50 + 20) v

v = 4

The final velocity is 4 m/s.

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a line passes through (8,-4) and has a slope 2/3. what is an equation in point slope form of the line? An equation of the line i
evablogger [386]

from the question

x₁ = x-coordinate = 8

y₁ = y-coordinate = - 4

m = slope of line = 2/3

slope form of the line is given as

(y - y₁ ) = m (x - x₁)

inserting the values

(y - (- 4) ) = (2/3) (x - 8)

(3) (y + 4) = (2) (x - 8)

multiplying each term inside the bracket by 3  and 2 respective on left and right side

3y + 12 = 2 x - 16

2 x - 3 y - 16 - 12 = 0

2 x - 3 y - 28 = 0




7 0
3 years ago
What is the basic equation that defines velocity?
mr Goodwill [35]
Change in position (triangleV) divided by change in time (triangleT)
7 0
3 years ago
12 POINTS PLEASE HELP.
bazaltina [42]
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3 0
3 years ago
What is the equation for horizontal velocity
yan [13]
V(x) = V(ix)
v=d/delta t
3 0
3 years ago
Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 44.3 ◦ . The velo
Goshia [24]

Answer:

So airplane will be 1324.9453 m apart after 2.9 hour

Explanation:

So if we draw the vectors of a 2d graph we see that the difference in angles is  = 83 - 44.3 = 83-44.3=38.7^{\circ}

Distance traveled by first plane = 730×2.9 = 2117 m

And distance traveled by second plane = 590×2.9 = 1711 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 38.7.

Using the law of cosine, d^2 representing the distance between the planes, we see that:

d^2=2117^2 + 1711^2 -2\times (2117)\times (1711)cos(38.7)=1755480.2482

d = 1324.9453 m

4 0
3 years ago
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