If no extra acceleration is added to the rocket, then its velocity at time <em>t</em> is
<em>v</em> = 15 m/s - <em>g t</em>
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.
Also, recall that
<em>v</em>² - <em>u</em>² = 2 <em>a </em>∆<em>x</em>
where <em>u</em> is initial speed, <em>v</em> is final speed, <em>a</em> is acceleration, and ∆<em>x</em> is net displacement.
At the rocket's maximum height ∆<em>x</em>, the velocity is 0. So, the maximum height is
0² - (15 m/s)² = 2 (-<em>g</em>) ∆<em>x</em>
∆<em>x</em> = (15 m/s)² / (2 * (9.80 m/s²)) ≈ 11.48 m
But this assumes the rocket is launched from the ground. We're given that the rocket is launced from 3 m above the ground, so we need to add this to the height above. So the maximum height is closer to 14.48 m.
As mentioned before, this happens when vertical velocity is 0:
0 = 15 m/s - <em>g t</em>
<em>t</em> = (15 m/s) / (9.80 m/s²) ≈ 1.53 s
The intensity of a sound wave is defined as the amount of energy passing through a unit area of the wave front in unit of time.
Let's call
the mass of the glider and
the total mass of the seven washers hanging from the string.
The net force on the system is given by the weight of the hanging washers:
For Newton's second law, this net force is equal to the product between the total mass of the system (which is
) and the acceleration a:
So, if we equalize the two equations, we get
and from this we can find the acceleration:
Answer:
1 . What happens when you drop the stone?
Depending on the weight from which the stone was dropped, the glass might well break
2 depending on the size and weight and shape on the stone the glass might well break
3 depending on the density on the stone the stone might when float on the water
Explanition :
GIVE ME BRAINLESS PLEASE !!
<h2>Isaac Newton's First Law of Motion states, "A body at rest will remain at rest, and a body in motion will remain in motion unless it is acted upon by an external force." What, then, happens to a body when an external force is applied to it? That situation is described by Newton's Second Law of Motion. </h2><h2>
equation as ∑F = ma
</h2><h2>
</h2><h2>The large Σ (the Greek letter sigma) represents the vector sum of all the forces, or the net force, acting on a body. </h2><h2>
</h2><h2>It is rather difficult to imagine applying a constant force to a body for an indefinite length of time. In most cases, forces can only be applied for a limited time, producing what is called impulse. For a massive body moving in an inertial reference frame without any other forces such as friction acting on it, a certain impulse will cause a certain change in its velocity. The body might speed up, slow down or change direction, after which, the body will continue moving at a new constant velocity (unless, of course, the impulse causes the body to stop).
</h2><h2>
</h2><h2>There is one situation, however, in which we do encounter a constant force — the force due to gravitational acceleration, which causes massive bodies to exert a downward force on the Earth. In this case, the constant acceleration due to gravity is written as g, and Newton's Second Law becomes F = mg. Notice that in this case, F and g are not conventionally written as vectors, because they are always pointing in the same direction, down.
</h2><h2>
</h2><h2>The product of mass times gravitational acceleration, mg, is known as weight, which is just another kind of force. Without gravity, a massive body has no weight, and without a massive body, gravity cannot produce a force. In order to overcome gravity and lift a massive body, you must produce an upward force ma that is greater than the downward gravitational force mg. </h2><h2>
</h2><h2>Newton's second law in action
</h2><h2>Rockets traveling through space encompass all three of Newton's laws of motion.
</h2><h2>
</h2><h2>If the rocket needs to slow down, speed up, or change direction, a force is used to give it a push, typically coming from the engine. The amount of the force and the location where it is providing the push can change either or both the speed (the magnitude part of acceleration) and direction.
</h2><h2>
</h2><h2>Now that we know how a massive body in an inertial reference frame behaves when it subjected to an outside force, such as how the engines creating the push maneuver the rocket, what happens to the body that is exerting that force? That situation is described by Newton’s Third Law of Motion.</h2><h2 />
