Answer:
<h2>3.18 × 10²³ atoms</h2>
Explanation:
The number of atoms can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.529 × 6.02 × 10²³
We have the final answer as
<h3>3.18 × 10²³ atoms</h3>
Hope this helps you
<h3>
Answer:</h3>
Mole ratio of D to A is 1 : 4
<h3>
Explanation:</h3>
We are given the generic chemical equation;
4A + B → C + D
We are supposed to determine the mole ratio of D to A
What is mole ratio?
- Mole ratio is the ratio of the number of moles of reactants or products in a chemical reaction.
- We determine the mole ratio using the coefficients of reactants or products in question.
For example;
- In the equation, 4A + B → C + D, the coefficient of A is 4 while the coefficient of D is 1.
- This means, 4 moles of A reacts with 1 mole of b to produce 1 mole of C and 1 mole of D
- Thus, mole ratio of D to A is 1 : 4
Answer:
Percent yield of reaction is<em> 150%.</em>
Explanation:
Given data:
Percent yield = ?
Actual yield of SO₃ = 586.0 g
Mass of SO₂ = 705.0 g
Mass of O₂ = 80.0 g
Solution:
Chemical equation:
2SO₂ + O₂ → 2SO₃
Number of moles of SO₂:
Number of moles = mass/ molar mass
Number of moles = 586.0 g/ 64.1 g/mol
Number of moles = 9.1 mol
Number of moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 80.0 g/ 32g/mol
Number of moles = 2.5 mol
Now we will compare the mole of SO₃ with O₂ and SO₂.
SO₂ : SO₃
2 : 2
9.1 : 9.1
O₂ : SO₃
1 : 2
2.5 : 2×2.5 = 5
The number of moles of SO₃ produced by oxygen are less it will limiting reactant.
Theoretical yield of SO₃:
Mass = number of moles × molar mass
Mass = 5 mol × 80.1 g/mol
Mass = 400.5 g
Percent yield of reaction:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 586.0 g/ 400.5 g× 100
Percent yield = 1.5× 100
Percent yield = 150%
Answer:
Option (C) 1.30 moles
Explanation:
The following data were obtained from the question:
Volume (V) = 20L
Temperature (T) = 373K
Pressure (P) = 203 kPa
Gas constant (R) = 8.31 L.kPa/mol.K.
Number of mole (n) =...?
The number of mole of the gas in the container can obtained by applying the ideal gas equation as illustrated below:
PV = nRT
Divide both side by RT
n = PV /RT
n = 203 x 20 / 8.31 x 373
n = 1.30 mole.
Therefore, 1.30 mole of the gas is present in the container.
If the pressure on an ideal gas is increased, the volume of the gas will decrease. This can be predicted with the use of the ideal gas equation which is expressed as: PV = nRT. At constant temperature, we can say that pressure and volume are inversely related. Thus, as one value increase, the other decrease.
