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egoroff_w [7]
3 years ago
14

Which energy transformation is represented in the diagram?

Chemistry
2 answers:
zubka84 [21]3 years ago
7 0

Answer:

<h2>(A) is the answer</h2>

Explanation:

Paha777 [63]3 years ago
6 0

A nuclear to thermal and radiant

Explanation:

Nuclear fission is the disintegration of the force that holds the nucleus of the atom together, creating two different but lighter nuclei.

In nuclear fission, it seeks to break the force of attraction or nuclear force that joins the protons and neutrons that form the nucleus of an atom. Neutrons without electric charge are used against the nucleus of the atom to produce enough excitation energy to deform the nucleus into two halves.

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If an atom has 30 electrons and 35 neutrons, what is its approximate atomic mass? what is the name of this element?
Murljashka [212]
30 electrons = atomic number
Look at your periodic table. You will see zinc has a atomic number (the top number) of 30.

When you add 30 and 35 you get 65. The is the atoms ATOMIC MASS. So looking at zinc on the periodic table, look at its bottom number, which is its atomic mass. It will be 65.

This means the name of the element is ZINC.

Hope this helped!
6 0
3 years ago
Which section of elements in the periodic table are the best conductors of heat and electricity
const2013 [10]
The metals. Primarily the left side
4 0
3 years ago
HELPPPPPPPPPPP???????
svetoff [14.1K]

Answer:

new moon

when the moon is front of the sun its a new moon

7 0
3 years ago
Controls are defined as____
Alexeev081 [22]
A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable.
5 0
3 years ago
Use the de Broglie's Wave Equation to find the wavelength of an electron moving at 7.3 × 106 m/s. Please show your work. Note: h
ad-work [718]

Answer:

\lambda=9.96\times 10^{-11}\ m

Explanation:

The expression for the deBroglie wavelength is:

\lambda=\frac {h}{m\times v}

Where,  

\lambda is the deBroglie wavelength  

h is Planck's constant having value 6.62607\times 10^{-34}\ Js

m is the mass of electron having value 9.11\times 10^{-31}\ kg

v is the speed of electron.

Given that v = 7.3\times 10^6\ m/s

Applying in the equation as:

\lambda=\frac {h}{m\times v}

\lambda=\frac{6.62607\times 10^{-34}}{9.11\times 10^{-31}\times 7.3\times 10^6}\ m

\lambda=\frac{10^{-34}\times \:6.626}{10^{-25}\times \:66.503}\ m

\lambda=\frac{6.626}{10^9\times \:66.503}\ m

\lambda=9.96\times 10^{-11}\ m

6 0
3 years ago
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