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Dahasolnce [82]
2 years ago
13

What term is commonly used to describe the concept whereby the cost of manufactured products is composed of direct materials cos

t, direct labor cost, and variable factory overhead cost?
Mathematics
1 answer:
Bumek [7]2 years ago
7 0

Answer:

Variable costing

Step-by-step explanation:

The term variable costing is a concept that is used in managerial accounting. Variable costing is a type of costing methodology that includes the variable manufacturing costs. When we say variable manufacturing costs, what we mean essentially is the cost of the inputs of production that are not fixed in price. For example, the machinery are assets and are primarily under the fixed cost. Things like labor cost may not be fixed and can even vary day to day. So therefore, we do not count things like that as variable.

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A car can go from 0 m/s to 27 m/s in 4.5 seconds. If a net force of 6600 N acted on
xz_007 [3.2K]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Also these 2 :) determining the vertex and shifts/translations
Mrrafil [7]

Answer:

The answer to your question is below

Step-by-step explanation:

A) f(x) = x² + 4x + 1

Find the vertex

       y = x² + 4x + 1

-Subtract 1 in both sides

      y - 1 = x² + 4x

-Complete the perfect trinomial square in the right side

     y - 1 + (2)² = x² + 4x + (2)²

-Simplify

     y - 1 + 4 = (x + 2)²

     y + 3 = (x + 2)²

-Find the vertex

      V = (-2, -3)

B)

   f(x) = x²

   g(x) = (x - 4)² - 2      See the picture below

Shifted right           4 units

Shifted down         2 units

6 0
3 years ago
Jaydas house is located at (1,5). She can walk in a straight line to get to Christians house. A fast food restaurant is located
steposvetlana [31]

Answer:

C. (9,1)

Step-by-step explanation:

Let the coordinated of Jaydas House be:

A(x_1, y_1) = (1,5)

The coordinates of Christian's House be:

B( x_2, y_2)

Let the restaurant be

M(x_M, y_M) = (7,2)

The ratio is 3:1

So

m=3 and n=1

So by the formula of finding the point that divides lines into given ratios

x_M = \frac{nx_1+mx_2}{m+n}\\7 = \frac{(1)(1)+(3)x_2}{3+1}\\7 =  \frac{1+3x_2}{4}\\7*4 = 1 + 3x_2\\28-1=3x_2\\27=3x_2\\x_2 = \frac{27}{3}\\x_2 = 9\\y_M = \frac{ny_1+my_2}{m+n}\\2 = \frac{(1)(5)+(3)y_2}{3+1}\\2 =  \frac{5+3y_2}{4}\\2*4 = 5 + 3y_2\\8=5+3y_2\\8-5=3y_2\\3=3y_2\\y_2 = \frac{3}{3}\\y_2 = 1

Therefore the coordinates of Christian's house are (9,1)

Option C is correct ..

7 0
3 years ago
Do the ratios 9/6 and 2/1 form a proportion
valina [46]

Answer:

This is not a proportion

Step-by-step explanation:

Set up a proportion

9/6 = 2/1

Check with cross products

9*1 = 6*2

9 = 12

This is not true so they are not proportional

3 0
3 years ago
California University encourages professors to consider using e-textbooks instead of the traditional paper textbooks. Many cours
sergiy2304 [10]

Answer:

Step-by-step explanation:

Hello!

The variable is:

X: number of coursers taken by students during Fall 19 semester at California University that provide an e-texbook option.

The following data represents the number of courses and their point probabilities:

X:     0; 1;    2;       3;      4;     5

P(X): ? ; ?; 0.30; 0.25; 0.15; 0.10

First step is to calculate the missing point probabilities corresponding to observations X=0 and X=1

Now remember that the total sum of probabilities of a variable is 1.

So P(0) + P(1) + P(2) + P(3) + P(4) + P(5) = 1

P(0) + P(1) + 0.30 + 0.25 + 0.15 + 0.10 = 1

P(0) + P(1) + 0.80= 1

P(0) + P(1) = 1 - 0.8

P(0) + P(1) = 0.2

Now acording to the text, the probability that 1 course offers an e-book option is three times as likely as the probability of 0 courses offerig it.

If P(0)= x then P(1)= 3x, then:

x + 3x= 0.2

4x= 0.2

x= 0.2/4

x= 0.05

Wich means that P(0)= 0.05 and P(1)= 0.15, and the probability distribution for the variable is:

X:       0;        1;      2;       3;      4;     5

P(X): 0.05 ;0.15 ; 0.30; 0.25; 0.15; 0.10

F(X): 0.05; 0.2   ; 0.5  ; 0.75; 0.90;   1

The average value for this variable is:

E(X)= ∑x*P(X)= (0*0.05)+(1*0.15)+(2*0.3)+(3*0.25)+(4*0.15)+(5*0.10)= 2.6

If all courses that the university offers are above the average, the probability that all courses offer e.book options is:

P(2.6≤X≤5)= P(X≤5) - P(X<2.6)= P(X≤5) - P(X≤2)= 1 - 0.5= 0.5

I hope it helps!

3 0
3 years ago
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