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Basile [38]
3 years ago
6

A chemist finds that when platinum is added to a reaction, the reaction speeds up. He thinks the platinum may be acting as a cat

alyst. What measurement should the chemist make to determine whether it is a catalyst?
Measure the mass of the platinum before and after the reaction.
Measure the temperature of the solution before and after the reaction.
Measure the change in volume of the solution.
Measure the amount of gas released by the reaction.
Chemistry
2 answers:
kicyunya [14]3 years ago
8 0
Measure the mass of the platinum before and after the reaction 
as if it is acting as a catalyst the mass of platinum will remain unchanged as catalyst do not consume themselves in reaction  
SSSSS [86.1K]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

A substance that does not get consumed in a chemical reaction and helps in increasing rate of the reaction by lowering the activation energy is known as a catalyst.

Hence, when the chemist finds that reaction speeds up when platinum is added into the reaction then the chemist must calculate or measure the mass of platinum before and after the completion of reaction.

This is because if there occurs change in the mass of platinum then it means that platinum is not acting as a catalyst in the reaction.

Thus, we can conclude that chemist must measure the mass of the platinum to determine whether it is a catalyst.

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Answer:

helium=1,2atm

argon=2,8atm

Explanation:

partial is pressure exerted by each gas in a system since 30% is helium it means 70% is argon

argon =70%x4

helium=30%4

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Can you please tell me what is a rock?
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3 years ago
Can someone explain quantum number sets?
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Quantum numbers are based on the 4 parts namley:the principal quantum number (n), the orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms).
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3 years ago
What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
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Answer:

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

t_{1} = 22 °C

t_{2} = 33,6 °C

Q = 202 J

The formula is: Q = c * m * (t_{2} - t_{1})

c = \frac{Q}{m * (t_{2} - t_{1} )}

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

4 0
3 years ago
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cricket20 [7]

The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:

203 80 Hg → 203 81 + 0 -1 e

<h3>What is beta decay?</h3>

Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.

Beta particle is characterized by the possession of mass number 0 and atomic number -1.

This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:

203 80 Hg → 203 81 Tl + 0 -1 e

Learn more about beta radiation at: brainly.com/question/1580990

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