Hey there!:
Molar mass MgCl2 = 95.211 g/mol
Volume of solution in liters:
570.0 mL / 1000 => 0.57 L
Number of moles:
n = M * V
n = 2.00 * 0.57 => 1.14 moles of MgCl2
Therefore:
1 mol MgCl2 --------------- 95.211 g
1.14 moles MgCl2 ---------- ??
mass of MgCl2 = 1.14 * 95.211
mass of MgCl2 = 108.54 g
Hope that helps!
Answer:
36.08%
Explanation:
We are given the overall formula of the compound as: CuSO4•5H2O
Now, atomic mass of the elements are;
Cu = 63.55 g/mol
S = 32.07 g/mol
O = 16 g/mol
H20 = 18.02 g/mol
Now, let's calculate the total mass of the compound:
(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol
From the above, water in the compound is 5(H20)
Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol
Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%
Percentage of water = (90.1/249.72) × 100% = 36.08%
Answer:
The reaction would take place with racemization.
Explanation:
The compound (R)-3-bromo 3-methylhexane contains has the leaving group attached to a tertiary carbon atom. When the leaving group is attached to a tertiary carbon atom, the compound undergoes nucleophilic substitution via SN1 mechanism. This mechanism involves the formation of a planar carbocation intermediate. The nucleophile may attack this intermediate from either faces, leading to racemization of the product.
Answer:
The solution would need 13.9 g of KCl
Explanation:
0.75 m, means molal concentration
0.75 moles in 1 kg of solvent.
Let's think as an aqueous solution.
250 mL = 250 g, cause water density (1g/mL)
1000 g have 0.75 moles of solute
250 g will have (0.75 . 250)/1000 = 0.1875 moles of KCl
Let's convert that moles in mass (mol . molar mass)
0.1875 m . 74.55 g/m = 13.9 g
Explanation:
Light intensity influences the manufacture of plant food, stem length, leaf color and flowering. Generally speaking, plants grown in low light tend to be spindly with light green leaves. A similar plant grown in very bright light tends to be shorter, better branches, and have larger, dark green leaves.