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3 years ago

6

Wes melted some cheese over some tortilla chips to make nachos.

1 answer:

natima [27]3 years ago

4 0

Answer:

a

Explanation:

Because the mass would stay the same and the flavor did not change and neither did the color so the shape is the only thing that changed

You might be interested in

Which of the following is accurate in describing the placement and classification of iodine?

fenix001 [56]

You can answer this question by only searching the element in the periodic table.

The atomic number of iodine, I, is 53. It is placed in the column 17 (this is the Group) and row 5 (this is the Period).

The conclusion is that the iodine is located in Period 5, Group 17, and is classified as a nonmetal.

4 0

3 years ago

sample of substance X has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. If substance X has a mola

ELEN [110]

Number of moles ( substance x ):

1 mole --------- 58.45 g/mol
? mole --------- 326.0 g

326.0 x 1 / 58.45 => 5.577 moles

heat of fusion:

hf = Cal / moles

hf = 4325.8 Cal / 5.577 moles

hf = 775.65 cal/mol

hope this helps!

5 0

3 years ago

Read 2 more answers

According to Sam's soap recipe, she needs 855

AURORKA [14]

Answer:

gwbwhsusjhsbdsbdiddushsbdbdjsisshbwwiwjwbssidhdbdhdjdidjdbsbd

7 0

3 years ago

For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of

torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For $Al_2O_3$

Mass of $Al_2O_3$ = 4.07 g

Molar mass of $Al_2O_3$ = 101.96 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{4.07\ g}{101.96\ g/mol}$

$Moles\ of\ Al_2O_3= 0.0399\ mol$

According to the reaction:

$Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O$

1 mole of $Al_2O_3$ on reaction produces 1 mole of $Al_2(SO_4)_3$

So,

0.0399 mole of $Al_2O_3$ on reaction produces 0.0399 mole of $Al_2(SO_4)_3$

Moles of $Al_2(SO_4)_3$ obtained = 0.0399 mole

Molar mass of $Al_2(SO_4)_3$ = 342.2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0399= \frac{Mass}{342.2\ g/mol}$

$Mass= 13.7\ g$

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

$\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100$

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

$\%\ yield =\frac{10.4}{13.7}\times 100$

<u>% yield =76 %</u>

6 0

2 years ago

2) Two students are running in a cross country race. One has a mass of 60 kg, while the other has a mass of 70 kg. If they are b

Iteru [2.4K]

Answer:

The second student with mass 70kg has more momentum

Explanation:

Using the formula:

p = m × v

Where;

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

According to this question, two students are running in a cross country race.

Student 1 has the following; m = 60kg, v = 7m/s

Student 2 has the following; m = 70kg, v = 7m/s

Using p = mv

Student 1, p = 60 × 7 = 420 kgm/s

Student 2, p = 70 × 7 = 490 kgm/s

From the result of the above calculations, student 2 with mass 70kg has more momentum.

4 0

2 years ago