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8090 [49]
2 years ago
6

Wes melted some cheese over some tortilla chips to make nachos.

Chemistry
1 answer:
natima [27]2 years ago
4 0

Answer:

a

Explanation:

Because the mass would stay the same and the flavor did not change and neither did the color so the shape is the only thing that changed

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What is the balance equation for <br> _AI+_Pb(NO3)2—__Pb+__Ca(NO3)2
Firdavs [7]

Answer:

2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb

Explanation:

4 0
2 years ago
How many moles of the product fecl3 do you make, when 8moles of fe react with excess cl2
tatuchka [14]

To figure out questions related to reacting moles/masses, the first step is always to write a complete balanced equation.

2Fe (s) + 3Cl2 (g) → 2FeCl3 (s)

Since Cl2 is the excess reactant, and Fe is the limiting reactant, we can simply find the number of moles of the product by comparing the mole ratio of the limiting reactant to the mole ratio of the product from the equation.

From the equation, mole ratio of Fe:FeCl3 = 2:2 = 1:1, the number of moles of product is exactly the same as the number of moles of the limiting reactant, which makes it 8 moles.

Note that if the mole ratio is not 1:1, you have to do some calculations to make sure the no. of moles is balanced at the end. Which means, if the mole ratio happened to be 1:2, the no. of moles of the product would be 8x2=16 instead.

So, your answer is 8 moles.

7 0
3 years ago
Read 2 more answers
Predidt the direction and the relative value of the dipole moment of the following bond: C-Cl
WINSTONCH [101]

Answer:

D. C → Cl electronegativity difference > 0.5

Explanation:

The electro negativity of an atom in a compound refers to its ability to attract the electrons of a bond towards itself.

On the Pauling's scale, carbon has an electro negativity value of 2.55 while that of chlorine is 3.16. The difference in electro negativity between the both atoms is about 0.61.

The dipole is aslways directed towards the more electronegative atom. Hence the direction is ; C → Cl

5 0
3 years ago
- Equilibrium shifts for slightly soluble compounds The reaction for the formation of a saturated solution of silver bromide (Ag
RideAnS [48]

Answer:

1) Favor formation of reactant

2) Favor formation of product

3) Favor formation of product

4) Favor formation of product

5) Favor formation of product

Explanation:

The reaction is AgBr(s)--->Ag^{+}(aq)+Br^{-}(aq)

The reaction is endothermic

1. Adding hydrobromic acid (HBr)

It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.

2. Lowering the concentration of bromide (Br-) ions

As we are decreasing the the concentration of product it will favor formation of more products

3. Heating the concentrations

If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.

4. Adding solid silver bromide (AgBr)

If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products

5. Removing silver (Ag+) ions

Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.

3 0
3 years ago
A chemist titrates 150.0 mL of a 0.2653 M carbonic acid (H2CO3) solution with 0.2196 M NaOH solution at 25 °C. Calculate the pH
xxTIMURxx [149]

Answer:

9.3

Explanation:

This is long and complicated so get ready

We are going to use the conjugate base of carbonic acid with water to make carbonic acid and OH- (Na is simply a spectator ion and is irrelavent here)

Let the conjugate base be A- and Carbonic acid be HA

A- + H20 ⇄ HA + OH-

To find the concentration of A- we must find the concentration of the reactants given. We know this will be equal because it is a strong base and all of it disassociates.

to get moles of acid we take the concentration and multiply by liters to cancel

.2653 x .150 = .039795 mol HA

Because it is at equivalence point we know the moles will be equal. We are given the concentration so we only have to solve for liters

We plug it into the equation and found: .181 L

Now use moles and combined volums to fins concentrarion which is .120 M

Now plug that use the Ka converted to Kb to find the cincentrations of HA and OH-

Ka is (10^-3.60) = 2.4E-4

Kb x Ka is 10^-14

Kb = 3.98E-11

Now we know Kb = [HA] [OH] / [A-]

Solve for this through algebra by using x for the values you dont know

youll find x^2 = 3.3E-10

X = 1.8 E -5

this is the OH- concentration

-log [oh] = pOH

pOH = 4.73

We know 14-pOH = ph so pH= 9.3

6 0
3 years ago
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