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Serggg [28]
2 years ago
12

WHO FAST CAN YOU ANSWER ATOMS

Chemistry
1 answer:
guajiro [1.7K]2 years ago
8 0
The answer is A, I think ! Sorry if I’m wrong.
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The molar mass of a solid carboxylic acid is determined by titrating a known mass of the acid with a standardized solution of Na
laiz [17]

The answer is: II.The endpoint is recorded when the solution is dark red in color rather than light pink.

The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.  

Phenolphthalein is colorless in acidic solutions and pink in basic solutions. If  this indicator change color to dark red, more base is added and endpoint is not accurate.

If the the acid is spilled before titration, that does not make endpoint wrong and molar mass can be calculated.

In this example we can take acetic acid as carboxylic acid; basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).  

Balanced chemical reaction of acetic acid and sodium hydroxide:  

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Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.

8 0
3 years ago
Which of these substances most likely dissolve in water? check all that apply.
vlada-n [284]

The answer is:

glucose, a polar organic compound

silver nitrate, an ionic compound

<span>The two have net charges that enable them to attract with water molecules. Water molecules are partly charged because of the arrangement of electron clouds around the molecule. The oxygen atom in the molecule is more electronegative than the two hydrogens. Therefore water is able to form electrostatic attraction forces with the charged molecules</span>




8 0
3 years ago
When naming ionic compounds the ______________ is named first.
grandymaker [24]
The answer is metal. Metals are always named first in ionic compounds, like KNO3 for example. I hope this helps!
7 0
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