Answer:
36290 min = 604.8 hr.
Explanation:
1 lbs = 453.59237 grams.
∴ 2 lbs = 907.18474 grams.
<em><u>Using cross multiplication:</u></em>
500 mg of iron oxide dissolved → 20 minutes.
907184.74 mg of iron oxide dissolved → ??? minutes.
<em>∴ The time needed to dissolve 2 lbs of iron oxide =</em> (907184.74 mg)(20 min)/(500 mg) = <em>36290 min = 604.8 hr.</em>
As you can search and read the definition of a scientific experiment is the process of testing and finding the truth through this scientific method. Thus, all items are considered scientific experiment except for item "c" Ask her coworkers which solution they thick is better.
The arrows that represent the phase transitions in which heat energy is gained is : (A). 1, 2 and 3
<h3>Meaning of phase transitions</h3>
Phase transitions can be defined as the changing of matter from one form to another due to the addition or gaining of heat or due to the removal or loss of heat.
Phase transitions in matter are majorly between three phases which are: Solid, Liquid and Gas.
In conclusion, The arrows that represent the phase transitions in which heat energy is gained is : (A). 1, 2 and 3
Learn more about Phase transitions: brainly.com/question/11048831
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Answer: 24.1 L
Explanation:
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
![\frac{V_1}{T_1}=\frac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%3D%5Cfrac%7BV_2%7D%7BT_2%7D)
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
![V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K](https://tex.z-dn.net/?f=V_1%3D14.6L%5C%5CT_1%3D25.0%5EoC%3D%2825%2B273%29K%3D298K%5C%5CV_2%3D%3F%5C%5CT_2%3D220.0%5E0C%3D%28220%2B273%29K%3D493K)
Putting values in above equation, we get:
![\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L](https://tex.z-dn.net/?f=%5Cfrac%7B14.6%7D%7B298K%7D%3D%5Cfrac%7BV_2%7D%7B493%7D%5C%5C%5C%5CV_2%3D24.1L)
Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L