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Otrada [13]
3 years ago
12

What is the relationship between where the element is located within a "block" in the Periodic table and the superscripted value

(like the exponent) appearing at the end of the electron configuration for an element ?
Chemistry
2 answers:
9966 [12]3 years ago
8 0
The space where the element lies (in correspondence with it's own "block") is the number on the exponent.

EXAMPLE:
Carbon is second on it's block, it electronic configuration is 1s^2,2s^2,2p^2
F is fifth on it's block, it electronic configuration is 1s^2,2s^2,2p^5
Marysya12 [62]3 years ago
8 0

Answer:

The relationship between where elements is located in a block and super scripted value appearing at the end of the electronic configuration is that it gives information on the group the element exist in each block.

Explanation:

Blocks in the periodic table are divided as S, P, D AND F blocks.  Representing elements with a electronic configuration gives information on the block that the elements falls on . For example Sodium and fluorine configurations are as follows ;

Sodium → 1s²2s²2p∧6 3s∧1

flourine → 1s²2s²2p∧5

The outer shell that ends the configuration determines the block it belongs. In this case sodium belongs to the s block while fluorine belongs to the p blocks. Then the super scripted value which is 1 for sodium depict it belong to group 1 of the s blocks. The super scripted  value for fluorine which is 5 shows the element belongs to group 5 in the p blocks.

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Answer:

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Explanation:

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Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

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if we are comparing two gases,

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Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

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