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goblinko [34]
3 years ago
10

The rock cycle is driven by internally by heat from

Physics
2 answers:
rusak2 [61]3 years ago
4 0
Hi, earth and the sun would be your answer. 
kvasek [131]3 years ago
4 0

From Earth's interior and externally by energy from the sun

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How is energy transformed to chemical energy?
morpeh [17]

it is transfred through the basics

6 0
3 years ago
It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
Elena-2011 [213]

Answer:

B) the change in momentum.

Explanation:

The impulse is defined as the product between the force applied on an object (F) and the duration of the collision (\Delta t):

J=F \Delta t (1)

We can rewrite the force by using Newton's second law, as the product between mass (m) and acceleration (a):

F=ma

So, (1) becomes

J=ma \Delta t

Now we can also rewrite the acceleration as ratio between the change in velocity and change in time: a=\frac{\Delta v}{\Delta t}. If we substitute into the previous equation, we find

J=m\frac{\Delta v}{\Delta t}\Delta t=m\Delta v

And the quantity m\Delta v is equivalent to the change in momentum, \Delta p.

6 0
3 years ago
A 1300-kg car initially has a velocity of 22.2 m/s due south. It brakes to a stop over a 180 m distance.
Vaselesa [24]
The acceleration of the object which moves from an initial step to a full halt given the distance traveled can be calculated through the equation,
                                     d = v² / 2a
where d is distance, v is the velocity, and a is acceleration
Substituting the known values,
                                     180 = (22.2 m/s)² / 2(a)
The value of a is equal to 1.369 m/s²
The force needed for the object to be stopped is equal to the product of the mass and the acceleration.
                                      F = (1300 kg)(1.369 m/s²) 
                                            F = 1779.7 N
4 0
3 years ago
A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha
Nina [5.8K]

The average velocity over the interval 6\le t\le 10 is

\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}

where x(t) is the person's position at time t. I've taken the liberty of estimating x(6)\approx2.67\,\mathrm m. The closest choice among the answers is 0.8\,\dfrac{\mathrm m}{\mathrm s}.

7 0
3 years ago
Please help with #8... Thanks in advance
schepotkina [342]
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:

the general equation of acceleration is:

vf = vi + at

assuming the initial velocity (vi) is zero, the equation becomes:

vf = at 

v = at
6 0
3 years ago
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