Answer:
Explanation:
We shall apply Gauss's Law to find the solution .
flux entering the cube = E X A
= 46.8 X 147.1 X 147.1 Weber
flux going out of cube
= 114 x 147.1 X 147.1 Weber
Net flux going out
= ( 114 x 147.1 X 147.1 - 46.8 X 147.1 X 147.1 )
= 1454101.15 weber .
according to Gauss's law
q / ε₀ = 1.4541 x 10⁶ , q is required charge inside the cube.
q = 8.85 x 10⁻¹² x 1.4541 x 10⁶
= 12.868 x 10⁻⁶ C
= 12.868 μC.
Answer:
Turns of the primary coil: 500
Current in the primary coil: Ip= 0.01168A
Explanation:
Considering an ideal transformer I can propose the following equations:
Vp×Ip=Vs×Is
Vp= primary voltaje
Ip= primary current
Vs= secondary voltaje
Is= secondary current
Np×Vs=Ns×Vp
Np= turns of primary coil
Ns= turns of secondary coil
From these equations I can clear the number of turns of the primary coil:
Np= (Ns×Vp)/Vp = (20×120V)/4.8V = 500 turns
To determine the current in the secondary coil I use the following equation:
Is= (1.4W)/4.8V = 0.292A
Therefore I can determine the current in the primary coil with the following equation:
Ip= (Vs×Is)/Vp = (4.8V×0.292A)/120V = 0.01168A
Answer: You can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.
brainliest please :)
Answer:
Vb = v/2
Half of the speed of Car A before the collision
Explanation:
This problem can be solved by using conservation of momentum.
Since car B was stopped before the collision and its mass is twice the mass of A:
Also, since it is an elastic collision, car A stops after hitting car B. Rewriting the equation:
Therefore, the speed of car B after the collision is half of the speed of car A before the collision (v)
Vb = v/2
Answer:
C) 21 m/s
Explanation:
The general formula of the Doppler effect is:
where
f' is the apparent frequency
f is the original frequency
v is the speed of the wave in the medium
is the velocity of the receiver, positive if the receiver is moving towards the source
is the velocity of the source, positive if the source is moving away from the receiver
Here we have
f = 440 Hz
f' = 415 Hz
v = 343 m/s
(the observer is stationary)
is positive since we are considering when the train has passed the observer, so it is moving away from him
So we can rewrite the formula as
And solving for , we find the speed of the train
