The average speed of the plane is 875.999 m/s.
Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.
Mathematically, Average speed = Av = ![\frac{Total Distance}{Total Time}](https://tex.z-dn.net/?f=%5Cfrac%7BTotal%20Distance%7D%7BTotal%20Time%7D)
According to the question,
Speed of the plane away from its base V₁ = 730 m/s
Speed of the plane when it flies back V₂ = 1095 m/s
Plane flies the distance D = 404 km
Total Distance covered by the plane S = 404 * 2 km
(because the distance travelled by the plane when going away from the base and then flying back to the base is same)
Therefore S = 808 km = 808 ˣ 10³ m
Time taken by the plane while flying away from the base T₁ = ![\frac{D}{V1}](https://tex.z-dn.net/?f=%5Cfrac%7BD%7D%7BV1%7D)
T₁ =
= 553.425 s
Time taken by the plane while flying back to the base T₂ = ![\frac{D}{V2}](https://tex.z-dn.net/?f=%5Cfrac%7BD%7D%7BV2%7D)
T₂ =
= 368.949s
Total Time T = T₁ + T₂ = 922.375 s
Therefore Av =
=
m/s
=
m/s
= 875.999 m/s
The average speed of the plane will be 875.999 m/s.
To know more about Average speed,
brainly.com/question/28641761
#SPJ1