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3 years ago

The charge on a gamma ray is ____.

2 answers:

4 0

A gamma ray is the same physical thing as a radio wave or
a light wave. All of them are traveling electric and magnetic
fields, not charged particles. The waves and rays have no charge.

Tcecarenko [31]3 years ago

4 0

The charge on a gramma ray is zero

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A 2.40 cm × 2.40 cm square loop of wire with resistance 1.20×10−2 Ω has one edge parallel to a long straight wire. The near edge

Norma-Jean [14]

Answer:

current in loops is 52.73 μA

Explanation:

given data

side of square a = b = 2.40 cm = 0.024 m

resistance R = 1.20×10^−2 Ω

edge of the loop c = 1.20 cm = 0.012 m

rate of current = 120 A/s

to find out

current in the loop

solution

we know current formula that is

current = voltage / resistance .................a

so current = 1/R × d∅/dt

and we know here that

flux ∅ = ( μ×I×b / 2π ) × ln (a+c/c) ...............b

d∅/dt = ( μ×b / 2π ) × ln (a+c/c) × dI/dt ...........c

so from equation a we get here current

current = ( μ×b / 2πR ) × ln (a+c/c) × dI/dt

current = ( 4π× $10^{-7}$ ×0.024 / 2π(1.20× $10^{-2}$ ) × ln (0.024 + 0.012/0.012) × 120

solve it and we get current that is

current = 4 × $10^{-7}$ × 1.09861 × 120

current = 52.73 × $10^{-6}$ A

so here current in loops is 52.73 μA

8 0

3 years ago

The velocity of waves in a ripple tank is 10 centimeters per second, and standing waves are produced with nodes spaced 3.0 centi

Vsevolod [243]

<span>node spacing = half of wavelength = 3 cm velocity = 10 cm/s = freq * wavelength hench freq = 10/6 = 5/3 = 1.7 hz</span>

6 0

4 years ago

Read 2 more answers

a 3520 kg truck moving north at 18.5 m/s makes an INELASTIC collision with an 1480 kg car moving east after colliding they have

anyanavicka [17]

Answer:

Explanation:

An inelastic collision is one where 2 masses collide and stick together, moving as a single mass after the collision occurs. When we talk about this type of momentum conservation, the momentum is conserved always, but the kinetic momentum is not (the velocity changes when they collide). Because there is direction involved here, we use vector addition. The picture before the collision has the truck at a mass of 3520 kg moving north at a velocity of 18.5. The truck's momentum, then, is 3520(18.5) = 65100 kgm/s; coming at this truck is a car of mass 1480 kg traveling east at an unknown velocity. The car's momentum, then, is 1480v. The resulting vector (found when you pick up the car vector and stick the initial end of it to the terminal end of the truck's momentum vector) forms the hypotenuse of a right triangle where one leg is 65100 kgm/s, and the other leg is 1480v. Since we already know the final velocity of the 2 masses after the collision, we can use that to find the final momentum, which will serve as the resultant momentum vector in our equation (we'll get there in a sec). The final momentum of this collision is

p = mv and

p = (3520 + 1480)(13.6) so

p = 68000. Final momentum. The equation for this is a take-off of Pythagorean's Theorem and the one used to find the final magnitude of a resultant vector when you first began your vector math in physics. The equation is

$p_f=\sqrt{(p_{truck})^2+(p_{car})^2}$ which, in words, is

the final momentum after the collision is equal to the square root of the truck's momentum squared plus the car's momentum squared. Filling in:

$68000=\sqrt{(65100)^2+(1480v)^2}$ and

$(68000)^2=(65100)^2+(1480v)^2$ and

$4624000000=4238010000+2190400v^2$ and

$385990000=2190400v^2$ and

$176.2189554=v^2$ so

v = 13.3 m/s at 72.6°

6 0

3 years ago

Why isn't Coulomb's law valid for dielectric objects, even if they are spherically symmetrical?

marshall27 [118]

Answer:

Explanation:

The "traditional" form of Coulomb's law, explicitly the force between two point charges. To establish a similar relationship, you can use the integral form for a continuous charge distribution and calculate the field strength at a given point.

In the case of moving charges, we are in presence of a current, which generates magnetic effects that in turn exert force on moving charges, therefore, no longer can consider only the electrostatic force.

4 0

3 years ago

Identrying the speed of the Cart

aleksklad [387]

The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

<h3>How to calculate the speed?</h3>

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

Read more on speed here: brainly.com/question/17350470

#SPJ1

6 0

2 years ago

Read 2 more answers