In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t,
= 49.6/6 = 8.267 m/s
The correct answer is D. An average city
Explanation:
A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.
Answer:
1.04m
Explanation:
the distance is determined by the diameter of the trajectory.
you can find the radius of the trajectory by using the following formula:
mc : mass of the Big C = 0.303kg/mol/(6.02*10^{23}/mol)=5.03*10^{-25}kg
v: velocity of the ion = 50000m/s
B: magnetic constant = 0.3T
q: 1.6*10^{-19}C
By replacing you obtain:
the diameter wiil be:
d=2r=1.04m
the ion strikes the detector from 1.04m to the entrance of the spectrometer
Answer:
speed is -20.0155 m/s
and direction is downward
Explanation:
given data
mass of rocket = 1500 kg
rocket accelerates upward = 10 m/s²
time t = 2 s
maximum height = 530 m
to find out
speed and direction of the heavier fragment just after the explosion
solution
we use here principle of conservation of momentum that is
Mt Vt=M1 V1 + M2 V2 ................1
so here
first we find the initial velocity that is express as
v = a × t .....................2
v = 10 × 2
v = 20 m/s
and distance S
S =u × t + 0.5 × a × t² ...................3
S = 0 + 0.5 × 10 × 2²
S = 20 m
and now we find speed of the lighter piece that is
v² = v1² + 2 × a × S .................4
0 = v1² + 2 × -9.81 × (530-20)
v1² = 10006.2
v1 = 100.031 m/s
so now put all these in equation 1 we get
Mt Vt = M1 V1 + M2 V2
1500 × 20 = (1500 × 1/3 ) × 100.031 + (1500 × 2/3) + V2
30000 = 50015.5 + 1000 V2
V2 = -20.0155 m/s
so speed is -20.0155 m/s
that mean vertical component of second fragment will be move downward
I am pretty sure it is C.