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GenaCL600 [577]
3 years ago
6

The mass of a sample of iron is 31.5 g. The volume is 5 cm3. What is the density of iron in g/cm3?

Physics
1 answer:
ELEN [110]3 years ago
3 0
Answer : 6.3 g/cm3
Step by step explanation:
Density = mass/volume
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An object is falling downward at a rate of 25 m/s. Two seconds later, what is its acceleration?
zhenek [66]

acceleration times time falling

25*2

50 m*s^-1

6 0
4 years ago
At some of the greatest distances probed by telescopes, where many ordinary galaxies are too dim to be seen, we find the brillia
Simora [160]

Answer:

The brilliant galaxy centers are known as quasars. According to the astronomers quasars exists at the center o galaxies and in the center of galaxies there exists the black holes. Quasars are known as the brightest objects of the universe and they appear like a star in the telescopes.

Explanation:

5 0
3 years ago
Please help. All the information is in the image.
kondaur [170]

The tiger's position at time <em>t</em> is given by

<em>x</em> (horizontal) = (4.5 m/s) <em>t</em>

<em>y</em> (vertical) = 7.5 m - 1/2 <em>gt</em> ²

Solve <em>y</em> = 0 for <em>t</em> to find the time it takes for the tiger to reach the ground :

0 = 7.5 m - 1/2 (9.8 m/s²) <em>t</em> ²

===>   <em>t</em> = √(2 (7.5 m) / (9.8 m/s²)) ≈ 1.2 s

Evaluate <em>x</em> at this time :

<em>x</em> = (4.5 m/s) (1.2 s) ≈ 5.6 m

5 0
3 years ago
Car A and Car B approach each other
vagabundo [1.1K]

The original frequency of horn of Car A is 1071 Hz.

Explanation:

Doppler effect describes the change in the frequency of sound waves with respect to the observer. As the sound waves emitted from a source need to travel the air medium to reach observer, it will undergo loss in energy. So there will be change in its frequency compared to original frequency. Depending upon the direction of travel of source and observer the shifting of frequency will vary.

f'=\frac{v-v_{o} }{v-v_{s} } f

Here vo is the observer velocity and vs is the velocity of the source. So Vo = 15 m/s as car B is the observer and Vs = 35 m/s as car A is the source. And f is the frequency of sound wave at source that is car A.

Similarly, the doppler shift in frequency is the frequency of sound heard by car B which is f' = 1140 Hz. And v is the speed of sound that is v = 343 m/s

1140 = \frac{343-15}{343-35}*f= 1.0649 *f

f = 1140/1.0649= 1071 Hz.

Thus, the original frequency of horn of Car A is 1071 Hz.

3 0
4 years ago
The difference in potential between the cathode and anode of a spark plug is 14700 v. what energy does the electron give up as i
Verdich [7]
The energy the electron gives up passing between the electrodes is equal to the product between its charge and the potential difference between the electrodes:
\Delta U = e \Delta V
where 
e is the electron charge
\Delta V is the potential difference

Plugging numbers into the equation, we find that the electron gives up is
\Delta U = (1.6 \cdot 10^{-19} C)(14700 V)=2.35 \cdot 10^{-15} J
8 0
3 years ago
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