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Oliga [24]
3 years ago
11

Calculations made using Celsius or Fahrenheit will not work for gas law calculations

Physics
1 answer:
schepotkina [342]3 years ago
3 0
Yes, for temperature the unit should be in Kelvin, but that's easy (K = C + 273)
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4. Una cuerda de acero de piano mide 1.60 m de longitud y 0.20 cm de diámetro. ¿Cuál es la tensión en la cuerda si se estira 0.2
bazaltina [42]

Answer:

1030.83\ \text{N}

Explanation:

\Delta L = Cambio en la longitud de la cuerda = 0.25 cm

T = tensión en cuerda

A = Área de la cadena = \dfrac{\pi}{4}d^2

d = Diámetro de la cuerda = 0.2 cm

L = Longitud original de la cuerda = 1.6 m

El cambio de longitud de una cuerda viene dado por

\Delta L=\dfrac{TL}{AE}\\\Rightarrow T=\dfrac{\Delta LAE}{L}\\\Rightarrow T=\dfrac{0.25\times 10^{-2}\times \dfrac{\pi}{4}(0.2\times 10^{-2})^2\times 210\times 10^9}{1.6}\\\Rightarrow T=1030.84\ \text{N}

La tensión en la cuerda es 1030.84\ \text{N}.

8 0
3 years ago
All heat engines involve _____. the refrigeration cycle evaporation and condensation combustion
pishuonlain [190]
Combustion is the answer i just took the test
4 0
3 years ago
Read 2 more answers
A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 43 kg barbell straight up fro
Tasya [4]

Answer:

A. 231.77 J

B. 5330.71 J

C. 46 donuts

Explanation:

A. To lift the barbell once, she will have to extend it the full length of her arm. The work done will then be:

W = F * d

Where the force is the weight of the barbell.

F = m * g

Hence, the work done in lifting the barbell is:

W = m * g * d

W = 43 * 9.8 * 0.55

W = 231.77 J

B. If she does 23 repetitions, the total energy she expend will be equal to the Potential energy when the barbell is lifted multiplied by 23:

E = 23 * m * g * d

E = 23 * 231.77

E = 5330.71 J

C. 1 Joule = 4.184 calories

5330.71 Joules = 5330.71 * 4.184 = 22303.69

If 1 donut contains 490 calories, the number of donuts she will need will be:

N = 22303.69/490 = 45.5 donuts or 46 donuts

5 0
4 years ago
I need help with the circled one
Whitepunk [10]
Yes the answer is yes 
7 0
3 years ago
Write two examples of chemical properties and explain what they are
Gre4nikov [31]
Chemical Properties are properties of a substance that are seen during a chemical reaction. In other words, chemical properties cannot be found by looking/touching the substance. Those are its physical properties.

Examples

Flammability
toxicity
solubility
Acidity
Electronegativity
6 0
3 years ago
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