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Arturiano [62]
3 years ago
15

If the number of crests that pass a point in a given time increases, what has increased?

Physics
2 answers:
zysi [14]3 years ago
7 0
The frequency increasing makes the crests pass more quickly.  Frequency is a count of how many times per second an event occurs.  In waves, this event is the passing of an entire cycle.  Once the cycle has passed, the wave repeats.  The faster the wave repeats, the higher the frequency.  For this reason, frequency has units of hertz, Hz.  The unit of hertz is 1/s or "per second"
slavikrds [6]3 years ago
7 0

Answer:

I messed up on my first answer, I looked at the question wrong thinking that it said decreased not increased. And, indeed, frequency is correct. `:D

Explanation:

Hope this helps!

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A person takes a trip, driving with a constant speed of 99.5 km/h, except for a 26.0-min rest stop. The person's average speed i
Korvikt [17]

Answer:

1.65 h

121.39 km

Explanation:

Given that

speed of the driver, v = 99.5 km/h

time spent resting, t = 26 min

Average speed of the driver = 73.6 km/h

check attachment for calculation and how I arrived at the answer

7 0
2 years ago
If you kicked your mom <br><br> would she be mad?
vfiekz [6]

Answer:

Yes !

Explanation:

8 0
3 years ago
The mass of a coin is measured to be 12.5±0.1 g. The diameter is 2.8±0.1 cm and the thickness 2.1 ±0.1 mm. Calculate the average
Evgesh-ka [11]

The average density of the material from which the coin is made is 9.67 g/cm³.

<h3>Volume of the coin</h3>

The volume of the coin at the given diameter is calculated as follows;

V = Ah

where;

  • A is area of the coin
  • h is the thickness of the coin

V = πd²/4 x h

V = π(2.8)²/4  x (0.21 cm)

V = 1.293 cm³

<h3>average density of the coin</h3>

The average density of the material from which the coin is made is calculated as follows;

density = mass/volume

density = 12.5 g / (1.293 cm³)

density = 9.67 g/cm³

Thus, the average density of the material from which the coin is made is 9.67 g/cm³.

Learn more about average density here: brainly.com/question/1354972

#SPJ1

7 0
2 years ago
If two bicycles of same masses move at different velocities,it will be easier to stop the bicycle that is moving at lower veloci
s344n2d4d5 [400]

Answer:

It is easier to stop the bicycle moving at a lower velocity because it will require a <em>smaller force</em> to stop it when compared to a bicycle with a higher velocity that needs a<em> bigger force.</em>

Explanation:

The question above is related to "Newton's Law of Motion." According to the <em>Third Law of Motion</em>, whenever an object exerts a force on another object <em>(action force)</em>, an equal force is exerted against it. This force is of the same magnitude but opposite direction.

When it comes to moving bicycles, the force that stops their movement is called "friction." Applying the law of motion, the higher the speed, the higher the force<em> </em>that is needed to stop it while the lower the speed, the lower the force<em> </em>that is needed to stop it.

8 0
3 years ago
A closely wound search coil has an area of 3.21 cm2, 120 turns, and a resistance of 58.7 O. It is connected to a charge-measurin
Alexxx [7]

Answer:

The magnetic field in the System is 0.095T

Explanation:

To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.

By Faraday's law we know that

\epsilon = \frac{NBA}{t}

Where,

\epsilon  =electromotive force

N = Number of loops

B = Magnetic field

A = Area

t= Time

For Ohm's law we now that,

V = IR

Where,

I = Current

R = Resistance

V = Voltage (Same that the electromotive force at this case)

In this system we have that the resistance in series of coil and charge measuring device is given by,

R = R_c + R_d

And that the current can be expressed as function of charge and time, then

I = \frac{q}{t}

Equation Faraday's law and Ohm's law we have,

V = \epsilon

IR = \frac{NBA}{t}

(\frac{q}{t})(R_c+R_d) = \frac{NBA}{t}

Re-arrange for Magnetic Field B, we have

B = \frac{q(R_c+R_d)}{NA}

Our values are given as,

R_c = 58.7\Omega

R_d = 45.5\Omega

N = 120

q = 3.53*10^{-5}C

A = 3.21cm^2 = 3.21*10^{-4}m^2

Replacing,

B = \frac{(3.53*10^{-5})(58.7+45.5)}{120*3.21*10^{-4}}

B = 0.095T

Therefore the magnetic field in the System is 0.095T

3 0
3 years ago
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