Mary travelled 70 miles/hour due north.
2 answers:
Answer : The correct option is, Velocity.
Explanation :
Acceleration : It is defined as the rate of change of velocity of an object wit respect to the time. Acceleration is a vector quantity that means it depends on the magnitude and direction of an object. The S.I unit of acceleration is,
Distance : It is defined as the how far an object has traveled in time. Distance is a scalar quantity that means it is depends on the magnitude of an object only. The S.I unit of distance is,
Speed : It is defined as the distance traveled by an object in unit time. Speed is also a scalar quantity. The S.I unit of speed is,
Velocity : It is defined as the change in the position with respect to the time. Velocity is a vector quantity that means it depends on the magnitude and direction of an object. The S.I unit of velocity is,
Mary traveled 70 miles/hour due north. This is an example of velocity. 70 miles/hour tell us about the magnitude of the object and north tell us about the direction of an object.
Hence, the correct option is, velocity.
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Answer:
Explanation:
From the second law of Newton movement laws, we have:
, and we know that a is the acceleration, which definition is:
, so:
The next step is separate variables and integrate (the limits are at this way because at t=0 the block was at rest (v=0):
(This is the indefinite integral), the definite one is:
Answer:
a) -1.325 μC
b) 4.17μC
Explanation:
First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:
We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.
The electrostatic force is equal to:
K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2
Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:
Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:
Solving the quadratic equation:
for this values q_1 wil be:
So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC