All categories

3 years ago

"a musical tone sounded on a piano has a frequency of 261.6 hz and a wavelength of 1.31 m. what is the speed of the sound wave

2 answers:

7 0

To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.

Crazy boy [7]3 years ago

3 0

The answer is: 343m/s

You might be interested in

Draw a schematic diagram of a circuit consisting of a battery of five 2 V cells, a 5 ohm resistor, a 10 ohm resistor, a 15 ohm r

MakcuM [25]

Answer:

Current = 0.33 A

Explanation:

For diagram refer the attachment.

It is given that five cells of 2V are connected in series, so total voltage of the battery:

$\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V$

Three resistor of 5 $\Omega$ , 10 $\Omega$ , 15 $\Omega$ are connected in Series, so the net resistance:

$\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}$

$\dashrightarrow \: \: \sf R = 5 + 10 + 15$

${ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}$

According to ohm's law:

$\dashrightarrow \sf\: \: V = IR$

$\dashrightarrow \sf \: \: I = \dfrac{V}{R}$

On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 ${\pmb{\sf{\Omega}}}$ we get:

$\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}$

${ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}$

$\therefore$ The electric current passing through the above circuit when the key is closed will be <u>0.33 A</u>

4 0

2 years ago

Read 2 more answers

1. How far does a skydiver fall

GREYUIT [131]

Free fall without air resistance:

g=9.81 m/s²

t=235 s

h=?

h=0.5*g*t²

h=0.5*9.81*235²

h=270879m =270 km

5 0

3 years ago

A 300-W blender did 10,500J of work. how long was the blender running?

forsale [732]

Answer:

The blender was running for 35 seconds.

Explanation:

Given:

Power of the blender is, $P=300\ W$

Work done by the blender is, $W=10500\ J$

We know that, power is defined as the rate at which work is done by the body.

Here, we are given the power and work done and we are asked to find time taken.

Let the time of running of the blender be 't' seconds.

So, the power of the blender is given as:

$P=\frac{W}{t}$

Rewriting the above in terms of 't', we have

$t=\frac{W}{P}$

Plug in the given values and solve for 't'. This gives,

$t=\frac{10500}{300}\\t=35\ s$

Therefore, the blender was running for 35 seconds.

6 0

4 years ago

An airplane flies horizontally with a constant speed of 172.0 m/s at an altitude of 1390 m. A package is dropped out of the airp

Sever21 [200]

Answer:

(a) - 165.032 m/s

(b) 238.37 m/s

Explanation:

initial horizontal velocity, ux = 172 m/s

height, h = 1390 m

g = 9.8 m/s^2

Let it strikes the ground after time t.

Use second equation of motion in vertical direction

$s=ut+\frac{1}{2}at^{2}$

-1390 = 0 - 0.5 x 9.8 x t^2

t = 16.84 second

(a) Let vy be the vertical component of velocity as it strikes the ground

Use first equation of motion in vertical direction

vy = uy - gt

vy = 0 - 9.8 x 16.84

vy = - 165.032 m/s

Thus, the vertical component of velocity as it strikes the ground is 165.032 m/s downward direction.

(b)

The horizontal component of velocity remains constant throughout the motion.

vx = 172 m/s

vy = - 165.032 m/s

The resultant velocity is v.

$v=\sqrt{172^{2}+165.032^{2}}$

v = 238.37 m/s

Thus, teh velocity with which it hits the ground is 238.37 m/s.

8 0

4 years ago

What is the effective resistance between the points A and D? A) 1.3 Ω B) 2.2 Ω C) 10 Ω D) 12 Ω

Rudiy27

Answer:

B) 2.2 Ω

Explanation:

First of all, we should notice that the resistor placed between A and B is short-circuited. In fact, the current from point A will follow the wire above between A and C (which has zero resistance), so we can basically ignore the presence of the resistor between A and B, since it has no effect on the circuit.

Then, we can notice that the two resistors between CB and CD are in parallel to each other; therefore, their equivalent resistance is given by:

$\frac{1}{R}=\frac{1}{R_{BC}}+\frac{1}{R_{CD}}=\frac{1}{4.0 \Omega}+\frac{1}{5.0 \Omega}=\frac{9}{20 \Omega}\\R= \frac{20 \Omega}{9}=2.2 \Omega$

6 0

4 years ago