Answer:
The magnitude of the force between the two parallel wires is 0.0111 N.
Explanation:
Given;
length of the two parallel wires, L = 42 m
distance between the two wires, r = 0.03 m
current in both wires, I₁, I₂ = 6.3 A
Therefore, the magnitude of the repulsive force between the two parallel wires is given by;
Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.
Answer:
Energy = 780 Joules
Explanation:
Given the following data;
Power = 78 Watts
Time = 10 seconds
To find the energy transferred;
Energy refers to the amount or quantity of power which is being consumed by an individual, group of people or organization over a specific period of time.
Mathematically, energy is given by the formula;
Energy = power * time
Energy = 78 * 10
Energy = 780 Joules
Therefore, the amount of energy the turbine transferred is 780 Joules
Force = (mass) x (acceleration)
= (0.025 kg) x (5 m/s²)
= 0.125 Newton
♥ If the wind is strong enough it can do so.
♥ By having a strong enough wind you can blow out the fire before the flame can consume any more vapor.
♥ If the wind is fast enough, like a birthday cake candle for example, the wind will burn out.
