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timofeeve [1]
3 years ago
10

Calculate ΔH when 2 moles of ethanol (C2H5OH) reacts with excess oxygen according to the following thermochemical equation?C2H5O

H + 3O2 → 2CO2 + 3H2O ΔH = −1366.7 kJ
Chemistry
1 answer:
klio [65]3 years ago
5 0

Answer:

–2733.4 KJ

Explanation:

The balanced equation for the reaction is given below:

C₂H₅OH + 3O₂ —> 2CO₂ + 3H₂O

ΔH = −1366.7 kJ

From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:

From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.

Thus, enthalpy change (ΔH) obtained is –2733.4 KJ

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6 0
2 years ago
Two tons of water is pumped into a tank 15 ft. High in 5 minutes. Determine the power output of the pump. (Note: One ton is equa
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200 lb•ft/s

Explanation:

From the question given above, the following data were obtained:

Force (F) = 2 tons

Time (t) = 5 mins

Height (h) = 15 ft

Power (P) =?

Next, we shall convert 2 tons to pound. This can be obtained as follow:

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Finally, we shall determine the power of the pump. This can be obtained as follow:

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3 years ago
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