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3 years ago

What is the molar concentration of the Br⁻ ions in 0.17 M CaBr2(aq)?

1 answer:

4 0

CaBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of CaBr2 that dissolves.
CaBr2(s) --> Ca+(aq) + 2 Br⁻(aq)
[Br⁻] = 0.17 mol CaBr2/1L × 2 mol Br⁻ / 1 mol CaBr2 = 0.34 M
The answer to this question is [Br⁻] = 0.34 M

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1) The Lewis structure will be:

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