A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re
sults are shown in the data table below
based on the data table which unknown solution could be 0.1 M NaOH
1.A. 2.B
3.C. 4.D
The table is that it talks about is in the picture attached
based on the data table which unknown solution could be 0.1 M NaOH
1.A. 2.B
3.C. 4.D
The table is that it talks about is in the picture attached
1 answer:
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Answer:
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- <u>0.456M</u>
Explanation:
<u>1. Balanced molecular equation</u>
<u>2. Mole ratio</u>
<u>3. Moles of HNO₃</u>
- Number of moles = Molarity × Volume in liters
- n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃
<u>4. Moles Ba(OH)₂</u>
- n = 0.700M × 0.0310 liter = 0.0217 mol
<u>5. Limiting reactant</u>
Actual ratio:
Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.
Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.
<u>6. Final molarity of Ba(OH)₂</u>
- Molarity = number of moles / volume in liters
- Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M